尝试3次的Python用户名和密码 [英] Python username and password with 3 attempts

问题描述

刚开始使用python并投入了很多精力，但似乎做对了.

Just started python and racking my brains on this but can't seem to get it right.

print('Enter correct username and password combo to continue')
count=0
password=Hytu76E
username=bank_admin

while password!='Hytu76E' and username!='bank_admin' and count<4:
    username=input('Enter username: ') and password=input('Enter password: ')

    if password=='Hytu76E' and username=='bank_admin':
     print('Access granted')

    else:
        print('Access denied. Try again.')
        count-=1

语法错误，无法在第6行username = input上分配给运算符.

syntax error, can't assign to operator on line 6 username=input.

推荐答案

修复了代码以实现您要执行的操作:

Fixed the code to achieve what you are trying to do:

print('Enter correct username and password combo to continue')
count=0
while count < 3:
    username = input('Enter username: ')
    password = input('Enter password: ')
    if password=='Hytu76E' and username=='bank_admin':
        print('Access granted')
        break
    else:
        print('Access denied. Try again.')
        count += 1

已进行的更改:

• 删除了 username 和 password 的定义，因为它是多余的，可以省略
• 更改了 while 语句以计算3次 count
的迭代
• 仅在 if 语句中而不在 while
中验证凭据
• 将 count 的减少量更改为增加(从 count-= 更改为 count + = )
输入正确的凭据后，
• 打破循环

• Removed the definition of username and password since it is redundant and can be omitted
• Changed the while statement to count 3 iterations of count
• Validation of the credentials only in the if statement and not in the while
• Changed the decreasing of count to increasing (from count -= to count +=)
• break the loop when the right credentials are entered

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