读取二维表时出错 [英] Error when reading a two-dimensional table

问题描述

我正在尝试通过连接场地的相对边缘来创建无限的游戏场地.我收到以下错误:

I'm trying to create an infinite game field by connecting the opposite edges of the field. I get the following error:

错误:尝试索引字段?"(零值)

Error: attempting to index field '?' (a nil value)

该错误以粗体显示.据我了解，数组 field 在函数 drawField()中调用时不包含任何值，尽管在函数 clearField().我该如何修复数组，以便将其值保留在 clearField()之外?

The error is on the line in bold. As far as I understand, the array field does not contain any values when called in function drawField() despite it was filled with zeros in function clearField(). How can I fix the array so it keeps its values outside clearField()?

local black = 0x000000
local white = 0xFFFFFF

local field = {} 
local function clearField()
  for gx=1,displayWidth do
    if gx==displayWidth then
      field[1] = field[displayWidth+1]
    end
    field[gx] = {}
    for gy=1,displayHeight-3 do
      if gy==displayHeight-3 then
        field[gx][1] = field[gx][displayHeight-2]
      end
      field[gx][gy] = 0
    end
  end
end

--Field redraw
local function drawField()
  for x=1, #field do
    for y=1,x do
      **if field[x][y]==1 then**
        display.setBackground(white)
        display.setForeground(black)
      else
        display.setBackground(black)
        display.setForeground(white)
      end
      display.fill(x, y, 1, 1, " ")
    end
  end
end

-- Program Loop
clearField()
while true do
  local lastEvent = {event.pullFiltered(filter)}
  if lastEvent[1] == "touch" and lastEvent[5] == 0 then
    --State invertion
    if field[lastEvent[3]][lastEvent[4]]==1 then
      field[lastEvent[3]][lastEvent[4]] = 0
    else
      field[lastEvent[3]][lastEvent[4]] = 1
    end
    drawField()
  end
end

display 和 event 变量是库.该程序以 displayWidth = 160和 displayHeight = 50

display and event variables are libraries. The program was run with displayWidth = 160 and displayHeight = 50

推荐答案

field [1] = field [displayWidth + 1] 等同于 field [1] = nil ，因为您从未将值分配给 field [displayWidth + 1]

field[1] = field[displayWidth+1] is equivalent to field[1] = nil as you never assigned a value to field[displayWidth+1]

运行此命令以供自己查看:

Run this to see for yourself:

clearField()
print(field[1])
for k,v in pairs(field) do print(v[1]) end

因此，在您的外循环中，您为field创建了10个条目，但在第10次运行中，您删除了 field [1] ，这随后会导致在您尝试对inxex field [1]进行inxex时出现观察到的错误.如果field [x] [y] == 1则

So in your outer loop you create 10 entries for field but in the 10th run you delete field[1] which later causes the observed error as you're trying to inxex field[1] in if field[x][y]==1 then

您可以实现__index元方法来获得一个有点圆形的数组.像这样:

You could implement a __index metamethodt to get a somewhat circular array. Something like:

local a = {1,2,3,4}
setmetatable(a, {
  __index = function(t,i)
    local index = i%4
    index = index == 0 and 4 or index
    return t[index] end
})
for i = 1, 20 do print(a[i]) end

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