如何在sklearn cross_val_score中使用自定义评分功能 [英] How to use custom scoring function in sklearn cross_val_score
本文介绍了如何在sklearn cross_val_score中使用自定义评分功能的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想在 cross_val_score
函数中使用 Adjusted Rsquare .我尝试使用 make_scorer
函数,但无法正常工作.
I want to use Adjusted Rsquare in the cross_val_score
function. I tried with make_scorer
function but it is not working.
from sklearn.cross_validation import train_test_split
X_tr, X_test, y_tr, y_test = train_test_split(X, Y, test_size=0.2, random_state=0)
regression = LinearRegression(normalize=True)
from sklearn.metrics.scorer import make_scorer
from sklearn.metrics import r2_score
def adjusted_rsquare(y_true,y_pred):
adjusted_r_squared = 1 - (1-r2_score(y_true, y_pred))*(len(y_pred)-1)/(len(y_pred)-X_test.shape[1]-1)
return adjusted_r_squared
my_scorer = make_scorer(adjusted_rsquare, greater_is_better=True)
score = np.mean(cross_val_score(regression, X_tr, y_tr, scoring=my_scorer,cv=crossvalidation, n_jobs=1))
正在处理错误:
IndexError: positional indexers are out-of-bounds
有什么方法可以使用我的自定义函数,即; adjusted_rsquare
与 cross_val_score
?
Is there any way to use my custom function i.e; adjusted_rsquare
with cross_val_score
?
推荐答案
adjusted_rsquare(X,Y)
是一个数字,它不是一个函数,只需像这样创建计分器即可:
adjusted_rsquare(X,Y)
is a number, it's not a function, just create the scorer like this:
my_scorer = make_scorer(adjusted_rsquare, greater_is_better=True)
您还需要更改得分功能:
def adjusted_rsquare(y_true, y_pred, **kwargs):
这是您应该使用的原型.您将实际结果与应有的结果进行比较.
That's the prototype that you should use. You compare the actual result to the result it should have been.
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