getline函数的类型冲突 [英] conflicting types for getline function

问题描述

我的代码块中有一个getline函数的函数，但是在编译make文件时出现以下错误:

I have a function for getline function in my code block.But while compiling the make file i get the following error:

cc -DMAIN   -c -o terp.o terp.c
terp.c:130:15: error: conflicting types for ‘getline’
In file included from terp.c:2:0:
/usr/include/stdio.h:675:20: note: previous declaration of ‘getline’ was here 
make: *** [terp.o] Error 1

terp.c在130左右的部分:

The part terp.c around 130:

 PRIVATE char *getline()
 {
static int first_time_called=1;
if(!first_time_called)
    return 0;
first_time_called=0;
return Expr;
 }

推荐答案

至少有三种可能的解决方案.

There are at least three possible solutions.

1. 由于 getline()不在标准c库中，而是在POSIX(和GLIBC)中，可以切换为禁用其扩展名(它们在GCC中默认启用).尝试使用命令 cc -DMAIN -std = c99 -c -o terp.o terp.c 编译源代码.

1. As getline() is not in standard c library, but in POSIX (and GLIBC), there could be switch to disable its extension (they enabled by default in GCC). Try compiling your source with command cc -DMAIN -std=c99 -c -o terp.o terp.c.

如果需要POSIX扩展，则必须将 getline()函数重命名为其他名称.

If you need POSIX extensions, you have to rename your getline() function to something else.

从您的源中删除<​​code> #include< stdio.h> ，此错误消息将消失.但是，如果在源代码中使用POSIX的 getline()，您可能会感到困惑，因为它将被您的源代码代替.

Remove #include <stdio.h> from your source, this error message will disappear. But you may become confused if POSIX's getline() is used in your source code, as it will be replaced by yours.

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