Python Tuple转换为JSON [英] Python Tuple to dict to JSON

问题描述

我的数据

(('check_kvserver_mem_4500000', 2737L), 
 ('check_ethstatus', 250L), 
 ('check_ddos', 229L), 
 ('check_coredump', 193L),
 ('check_robot', 174L),
 ('check_disk_90_95', 155L))

进入此:打印json.dumps(data)

[["check_kvserver_mem_4500000", 2737], 
 ["check_ethstatus", 250],
 ["check_ddos", 229],
 ["check_coredump", 193], 
 ["check_disk_90_95", 155]]

我想要类似的数据

{["check_kvserver_mem_4500000", 2737],
 ["check_ethstatus", 250]
 ["check_ddos", 229], 
 ["check_coredump", 193], 
 ["check_disk_90_95", 155]}

或

 {"check_kvserver_mem_4500000":2737,
  "check_ethstatus":250,
  "check_ddos":229, 
  "check_coredump":193,
  "check_disk_90_95":155}

推荐答案

您想要一个JSON对象作为结果，但是您的数据没有键/值结构.因此， json.dumps(data)在生成JSON列表而不是对象方面做得正确.无法在无效的JSON对象上匹配Python元组元组.

You want a JSON Object as a result but your data has no key/value structure. So json.dumps(data) is doing the right thing in generating a JSON List, not an Object. A Python tuple of tuples can not be matched on an invalid JSON Object.

修改

更改问题后(并在执行此操作时删除了我的美丽编辑)，您的问题就可以得到答案.

After you changed your question (and deleted my beautiful edits while doing this), your question can be answered.

data = (('check_kvserver_mem_4500000', 2737L),
        ('check_ethstatus', 250L),
        ('check_ddos', 229L),
        ('check_coredump', 193L),
        ('check_robot', 174L),
        ('check_disk_90_95', 155L))
print json.dumps(dict(data))

结果是:

'{"check_disk_90_95": 155, "check_coredump": 193, "check_robot": 174,
  "check_kvserver_mem_4500000": 2737, "check_ddos": 229, "check_ethstatus": 250}'

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