来自前向工程 EERD 的 Workbench 8.0 中的错误代码 1064 [英] Error Code 1064 in Workbench 8.0 from forward engineered EERD

查看:66
本文介绍了来自前向工程 EERD 的 Workbench 8.0 中的错误代码 1064的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我从前向工程数据库中收到以下错误:

I get the following error from my forward engineered database:

错误代码:1064.您的SQL语法有错误;请参见.检查与您的MariaDB服务器版本相对应的手册以获取正确的语法,以在'CONSTRAINT fk_Employees_EmployeeTitle1 FOREIGN KEY(第9行的"EmployeeTitle_EmpT"

Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ' CONSTRAINT fk_Employees_EmployeeTitle1 FOREIGN KEY (`EmployeeTitle_EmpT' at line 9

代码对我来说看起来不错,我也不知道从哪里可以开始使用它.代码如下:

The code looks good to me and I have no idea where to go from here to make it work. The code is as follows:

-- MySQL Workbench Forward Engineering

SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='ONLY_FULL_GROUP_BY,STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_ENGINE_SUBSTITUTION';

-- -----------------------------------------------------
-- Schema A2Lewis
-- -----------------------------------------------------

-- -----------------------------------------------------
-- Schema A2Lewis
-- -----------------------------------------------------
CREATE SCHEMA IF NOT EXISTS `A2Lewis` DEFAULT CHARACTER SET utf8 ;
USE `A2Lewis` ;

-- -----------------------------------------------------
-- Table `A2Lewis`.`EmployeeTitle`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `A2Lewis`.`EmployeeTitle` (
  `EmpTitleID` INT NOT NULL,
  `EmpTitle` VARCHAR(45) NULL,
  PRIMARY KEY (`EmpTitleID`))
ENGINE = InnoDB;

INSERT INTO EmployeeTitle VALUES
(01, "Sales Representative"),
(02, "Tour Guide");
-- -----------------------------------------------------
-- Table `A2Lewis`.`Employees`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `A2Lewis`.`Employees` (
  `empID` INT NOT NULL,
  `empFirst` VARCHAR(45) NULL,
  `empLast` VARCHAR(45) NULL,
  `empWage` DECIMAL(4,2) NULL,
  `empPhone` CHAR(10) NULL,
  `EmployeeTitle_EmpTitleID` INT NOT NULL,
  PRIMARY KEY (`empID`),
  INDEX `fk_Employees_EmployeeTitle1_idx` (`EmployeeTitle_EmpTitleID` ASC) VISIBLE,
  CONSTRAINT `fk_Employees_EmployeeTitle1`
    FOREIGN KEY (`EmployeeTitle_EmpTitleID`)
    REFERENCES `A2Lewis`.`EmployeeTitle` (`EmpTitleID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

INSERT INTO Employees VALUES
(01, "Thomas", "Lewis", 12.00, 6134493075, 01),
(02, "John", "Doe", 11.25, 6135554267, 01),
(03, "Sarah", "Simon", 11.00, 6135554582, 01), 
(04, "Connor", "Toth", 15.00, 6135557894, 02),
(05, "James", "Young", 13.50, 6135554528, 02),
(06, "Ben", "Zimmer", 14.75, 6135554287, 02);
-- -----------------------------------------------------
-- Table `A2Lewis`.`Tours`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `A2Lewis`.`Tours` (
  `tourID` INT NOT NULL,
  `tourName` VARCHAR(45) NULL,
  `tourMeetLoc` VARCHAR(45) NULL,
  `tourDist` INT NULL,
  `tourMaxCust` INT NULL,
  `tourCost` DECIMAL(5,2) NULL,
  `tourProvince` VARCHAR(45) NULL,
  `tourDate` DATE NULL,
  PRIMARY KEY (`tourID`))
ENGINE = InnoDB;

INSERT INTO Tours VALUES
(01, "Sightseeing tour of Halifax", "City of Halifax", 15, 35, 585.00, "Nova Scotia", 2019-03-05),
(02, "The Sun and Sand Trail", "City of Bathurst", 250, 20, 999.99, "New Brunswick", 2019-07-10),
(03, "Quebec Countryside Tour", "Chemin du Roy", 89, 30, 800.00, "Quebec", 2019-10-15);
-- -----------------------------------------------------
-- Table `A2Lewis`.`Seasons`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `A2Lewis`.`Seasons` (
  `seasID` INT NOT NULL,
  `seasName` VARCHAR(45) NULL,
  PRIMARY KEY (`seasID`))
ENGINE = InnoDB;

INSERT INTO Seasons VALUES
(01, "Early Spring"),
(02, "Mid Spring"),
(03, "Late Spring"),
(04, "Early Summer"),
(05, "Mid Summer"),
(06, "Late Summer"),
(07, "Early Fall"),
(08, "Mid Fall"),
(09, "Late Fall");
-- -----------------------------------------------------
-- Table `A2Lewis`.`Equipment`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `A2Lewis`.`Equipment` (
  `equipID` INT NOT NULL,
  `equipDescr` VARCHAR(45) NULL,
  `equipPrice` DECIMAL(4,2) NULL,
  `Tours_tourID` INT NOT NULL,
  PRIMARY KEY (`equipID`),
  INDEX `fk_Equipment_Tours1_idx` (`Tours_tourID` ASC) VISIBLE,
  CONSTRAINT `fk_Equipment_Tours1`
    FOREIGN KEY (`Tours_tourID`)
    REFERENCES `A2Lewis`.`Tours` (`tourID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

INSERT INTO Equipment VALUES
(01, "Four Person Tent", 89.00, 02),
(02, "Adult Bicycle", 50.00, 03);
-- -----------------------------------------------------
-- Table `A2Lewis`.`Customers`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `A2Lewis`.`Customers` (
  `custID` INT NOT NULL,
  `custFirst` VARCHAR(45) NOT NULL,
  `custLast` VARCHAR(45) NOT NULL,
  `cust65` TINYINT NOT NULL,
  `custStud` TINYINT NOT NULL,
  PRIMARY KEY (`custID`))
ENGINE = InnoDB;

INSERT INTO Customers VALUES
(01, "Thomas", "O'Neill", 0, 0),
(02, "Melissa", "Kennedy", 0, 1),
(03, "Craig", "Smith", 0, 0);
-- -----------------------------------------------------
-- Table `A2Lewis`.`Reservation`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `A2Lewis`.`Reservation` (
  `reservID` INT NOT NULL,
  `Tours_tourID` INT NOT NULL,
  `Employees_empID` INT NOT NULL,
  `Customers_custID` INT NOT NULL,
  PRIMARY KEY (`reservID`, `Employees_empID`),
  INDEX `fk_Booking_Tours1_idx` (`Tours_tourID` ASC) VISIBLE,
  INDEX `fk_Booking_Employees1_idx` (`Employees_empID` ASC) VISIBLE,
  INDEX `fk_Reservation_Customers1_idx` (`Customers_custID` ASC) VISIBLE,
  CONSTRAINT `fk_Booking_Tours1`
    FOREIGN KEY (`Tours_tourID`)
    REFERENCES `A2Lewis`.`Tours` (`tourID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_Booking_Employees1`
    FOREIGN KEY (`Employees_empID`)
    REFERENCES `A2Lewis`.`Employees` (`empID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_Reservation_Customers1`
    FOREIGN KEY (`Customers_custID`)
    REFERENCES `A2Lewis`.`Customers` (`custID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

INSERT INTO Reservation VALUES
(01, 01, 04, 01),
(02, 02, 05, 02),
(03, 03, 06, 03);
-- -----------------------------------------------------
-- Table `A2Lewis`.`Tours_has_Seasons`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `A2Lewis`.`Tours_has_Seasons` (
  `Tours_tourID` INT NOT NULL,
  `Seasons_seasID` INT NOT NULL,
  PRIMARY KEY (`Tours_tourID`, `Seasons_seasID`),
  INDEX `fk_Tours_has_Seasons_Seasons1_idx` (`Seasons_seasID` ASC) VISIBLE,
  INDEX `fk_Tours_has_Seasons_Tours1_idx` (`Tours_tourID` ASC) VISIBLE,
  CONSTRAINT `fk_Tours_has_Seasons_Tours1`
    FOREIGN KEY (`Tours_tourID`)
    REFERENCES `A2Lewis`.`Tours` (`tourID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_Tours_has_Seasons_Seasons1`
    FOREIGN KEY (`Seasons_seasID`)
    REFERENCES `A2Lewis`.`Seasons` (`seasID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

INSERT INTO Tours_has_Seasons VALUES
(01,01),
(02,05),
(03,07);

SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;

推荐答案

该错误是由于MySQL与MariaDB不兼容而引起的.

The error is caused because of incompatibility between MySQL and MariaDB.

该脚本显然适用于MySQL,但它在MariaDB上运行.尽管MariaDB最初与MySQL 100%兼容,但现在两个数据库都出现了分歧.许多人认为MariaDB现在更先进了,但事实是,他们现在在各地之间存在小/大差异.

This script is apparently for MySQL, but it's run on MariaDB. Even though MariaDB was originally 100% compatible with MySQL both databases have now diverged. Many people consider MariaDB more advanced now, but that fact is they now have small/big differences here and there.

在这种情况下,创建索引时,MariaDB不支持关键字 VISIBLE .而不是使用:

In this case, when creating an index, the keyword VISIBLE is not supported by MariaDB. Instead of using:

CREATE TABLE IF NOT EXISTS `A2Lewis`.`Employees` (
  `empID` INT NOT NULL,
  `empFirst` VARCHAR(45) NULL,
  `empLast` VARCHAR(45) NULL,
  `empWage` DECIMAL(4,2) NULL,
  `empPhone` CHAR(10) NULL,
  `EmployeeTitle_EmpTitleID` INT NOT NULL,
  PRIMARY KEY (`empID`),
  INDEX `fk_Employees_EmployeeTitle1_idx` (`EmployeeTitle_EmpTitleID` ASC) VISIBLE,
  CONSTRAINT `fk_Employees_EmployeeTitle1`
    FOREIGN KEY (`EmployeeTitle_EmpTitleID`)
    REFERENCES `A2Lewis`.`EmployeeTitle` (`EmpTitleID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

使用:

CREATE TABLE IF NOT EXISTS `A2Lewis`.`Employees` (
  `empID` INT NOT NULL,
  `empFirst` VARCHAR(45) NULL,
  `empLast` VARCHAR(45) NULL,
  `empWage` DECIMAL(4,2) NULL,
  `empPhone` CHAR(10) NULL,
  `EmployeeTitle_EmpTitleID` INT NOT NULL,
  PRIMARY KEY (`empID`),
  INDEX `fk_Employees_EmployeeTitle1_idx` (`EmployeeTitle_EmpTitleID` ASC),
  CONSTRAINT `fk_Employees_EmployeeTitle1`
    FOREIGN KEY (`EmployeeTitle_EmpTitleID`)
    REFERENCES `A2Lewis`.`EmployeeTitle` (`EmpTitleID`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

第二个查询(对于MariaDB)不需要 VISIBLE ,因为默认情况下索引在MariaDB中可见.

The second query (for MariaDB) does not require VISIBLE since indexes are visible by default in MariaDB.

这篇关于来自前向工程 EERD 的 Workbench 8.0 中的错误代码 1064的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆