如何在 Matplotlib 中根据斜率和截距添加线? [英] How to add line based on slope and intercept in Matplotlib?

问题描述

在R中，有一个名为 abline 的函数，其中可以根据截距(第一个参数)和斜率(第二个参数)的指定在绘图上绘制一条线.例如，

In R, there is a function called abline in which a line can be drawn on a plot based on the specification of the intercept (first argument) and the slope (second argument). For instance,

plot(1:10, 1:10)
abline(0, 1)

其中截距为0且斜率为1的线跨越了图的整个范围.Matplotlib中有这样的功能吗?

where the line with an intercept of 0 and the slope of 1 spans the entire range of the plot. Is there such a function in Matplotlib?

推荐答案

很多这些解决方案都专注于在绘图中添加一条适合数据的线.这是根据斜率和截距向图中添加任意线的简单解决方案.

A lot of these solutions are focusing on adding a line to the plot that fits the data. Here's a simple solution for adding an arbitrary line to the plot based on a slope and intercept.

import matplotlib.pyplot as plt 
import numpy as np    

def abline(slope, intercept):
    """Plot a line from slope and intercept"""
    axes = plt.gca()
    x_vals = np.array(axes.get_xlim())
    y_vals = intercept + slope * x_vals
    plt.plot(x_vals, y_vals, '--')

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