是否可以设置更高的轴标签的z索引? [英] Is it possible to set higher z-index of the axis labels?
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问题描述
在以下代码中,轴的代码标签隐藏在图形线的后面:
将 numpy 导入为 np导入matplotlib.pyplot作为pltX = np.linspace(-np.pi,np.pi,256,端点=真)C,S = np.cos(X), np.sin(X)plt.plot(X,C)plt.plot(X,S)plt.xticks([-np.pi,-np.pi/2,0,np.pi/2,np.pi],[r'$-\pi$', r'$-\pi/2$', r'$0$', r'$+\pi/2$', r'$+\pi$'])plt.yticks([-1, 0, +1],[r'$-1$', r'$0$', r'$+1$'])ax = plt.gca()ax.spines ['right'].set_color('none')ax.spines['top'].set_color('none')ax.xaxis.set_ticks_position('底部')ax.spines['bottom'].set_position(('data',0))ax.yaxis.set_ticks_position('left')ax.spines['left'].set_position(('data',0))用于ax.get_xticklabels()+ ax.get_yticklabels()中的标签:label.set_fontsize(14)label.set_bbox(dict(facecolor='white', edgecolor='None', alpha=0.75))plt.show()
您会发现很难看到例如 -pi
.有没有办法把轴标签放在前面?
解决方案
有一个
In the following code labels of the axis get hidden behind the graph lines:
import numpy as np
import matplotlib.pyplot as plt
X = np.linspace(-np.pi, np.pi, 256, endpoint=True)
C,S = np.cos(X), np.sin(X)
plt.plot(X,C)
plt.plot(X,S)
plt.xticks([-np.pi, -np.pi/2, 0, np.pi/2, np.pi],
[r'$-\pi$', r'$-\pi/2$', r'$0$', r'$+\pi/2$', r'$+\pi$'])
plt.yticks([-1, 0, +1],
[r'$-1$', r'$0$', r'$+1$'])
ax = plt.gca()
ax.spines['right'].set_color('none')
ax.spines['top'].set_color('none')
ax.xaxis.set_ticks_position('bottom')
ax.spines['bottom'].set_position(('data',0))
ax.yaxis.set_ticks_position('left')
ax.spines['left'].set_position(('data',0))
for label in ax.get_xticklabels() + ax.get_yticklabels():
label.set_fontsize(14)
label.set_bbox(dict(facecolor='white', edgecolor='None', alpha=0.75 ))
plt.show()
You can see that for instance -pi
is hard to see. Is there a way to put axis labels up front?
解决方案
There is an rcParameter axes.axisbelow
which steers exactly this behaviour:
axes.axisbelow
: draw axis gridlines and ticks
- below patches (True);
- above patches but below lines ('line');
- or above all (False)
If you set
plt.rcParams["axes.axisbelow"] = False
at the top of the script, gridlines and tick(label)s are drawn on top of everything else. The result would then look like
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