旋转图形但不旋转图例 [英] Rotate a figure but not the legend

问题描述

我有一个要旋转 90 度的图形.问题是图例也会旋转.

有没有办法只旋转图形?甚至能够将图例的旋转属性设置为90度也可以.

例如对于xticks，我正在使用 plt.xticks(range(len(mu_mse.index))，x_labs，rotation ='vertical')

解决方案

您可以查看关于

I have a figure that I want to rotate by 90 degrees. The problem is that also the legend rotates.

Is there a way to rotate only the figure? Even be able to set the rotation attribute of the legend to 90 degrees would be fine.

For the xticks for example I am using plt.xticks(range(len(mu_mse.index)), x_labs, rotation='vertical')

解决方案

You can check the demo example about floating axes for several uses of rotation. In this case you will only rotate the axes and than make the normal call for a legend.

You'll need to make the adjustments for position of legend, limits of the plot and so on, but a quick look at this example should provide you the logic behind it:

from matplotlib.transforms import Affine2D
import mpl_toolkits.axisartist.floating_axes as floating_axes
import numpy as np
import mpl_toolkits.axisartist.angle_helper as angle_helper
from matplotlib.projections import PolarAxes
from mpl_toolkits.axisartist.grid_finder import (FixedLocator, MaxNLocator,
                                                 DictFormatter)
import matplotlib.pyplot as plt


def setup_axes1(fig, rect):
    """
    A simple one.
    """
    tr = Affine2D().scale(2, 1).rotate_deg(30)

    grid_helper = floating_axes.GridHelperCurveLinear(
        tr, extremes=(0, 100, 0, 100))

    ax1 = floating_axes.FloatingSubplot(fig, rect, grid_helper=grid_helper)
    fig.add_subplot(ax1)

    aux_ax = ax1.get_aux_axes(tr)

    grid_helper.grid_finder.grid_locator1._nbins = 4
    grid_helper.grid_finder.grid_locator2._nbins = 4

    return ax1, aux_ax

fig = plt.figure()

x = range(100)
y = x + np.random.randint(-10,10,100)
ax1, aux_ax1 = setup_axes1(fig, 111)
aux_ax1.scatter(x,y,c='green',label='green')
aux_ax1.scatter(y,x,c='purple',label='purple')
ax1.legend()

plt.show()

This particular recipe (adapted from the link at the top of this answer) results in this:

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