绘制误差线(百分位) [英] Plot error bars (percentile)

问题描述

我对 python 很陌生，我需要一些帮助.我想在我的图上绘制相当于 1sigma 标准差的误差线作为分布的第 16 个和第 84 个百分位值.我尝试过(使用 matplotlib):

I'm quite new to python and I need some help. I would like to plot errorbars equivalent to 1sigma standard deviations on my plot as the 16th and 84th percentile values of the distributions. I tried with (using matplotlib):

err=np.std(x)

但它只是给了我标准偏差.谢谢.

but it just gives me the standard deviations. Thanks.

推荐答案

如果你想要垂直误差线

 ax = plt.gca()
 ax.errorbar(x, y, yerr=np.vstack([error_low, error_high]))
 plt.draw()

其中error_low 和error_high 是与x 和y 长度相同的一维序列.误差线绘制在 y [i]-error_low [i] 和 y [i] + error_high [i] 处.

where error_low and error_high are 1D sequences of the same length an x and y. The error bars are drawn at y[i] - error_low[i] and y[i] + error_high[i].

matplotlib 只是绘制你告诉它的内容，提供语义是你的工作.

matplotlib just draws what you tell it to, it is your job to provide the semantics.

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