仅在matplotlib中绘制带有边框的矩形 [英] Drawing rectangle with border only in matplotlib

问题描述

所以我找到了以下代码

So I found the following code here:

from matplotlib import pyplot as plt
from matplotlib.patches import Rectangle
someX, someY = 0.5, 0.5
plt.figure()
currentAxis = plt.gca()
currentAxis.add_patch(Rectangle((someX - .1, someY - .1), 0.2, 0.2,alpha=1))
plt.show()

这给出了:

但我想要的是一个只有蓝色边框且内部透明的矩形.我该怎么办?

But what I want is a rectangle with only a blue border and inside of it to be transparent. How can I do this?

推荐答案

您只需要将 facecolor 设置为字符串"none"(而不是python None )

You just need to set the facecolor to the string 'none' (not the python None)

from matplotlib import pyplot as plt
from matplotlib.patches import Rectangle
someX, someY = 0.5, 0.5
fig,ax = plt.subplots()
currentAxis = plt.gca()
currentAxis.add_patch(Rectangle((someX - 0.1, someY - 0.1), 0.2, 0.2,
                      alpha=1, facecolor='none'))

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