在matplotlib中用圆剪裁一个triagle [英] clipping a triagle with a circle in matplotlib

问题描述

我想画一个三角形，但是侧面之一必须是一个圆弧段.该示例不起作用:需要清除圆圈外的所有蓝色.可以直接完成而无需自己计算整个轮廓吗?

I would like to draw a triangle, but one of the sides needs to be a circle segment. The example is not working: all blue outside the circle needs to be removed. Can this be done directly, without calculating the entire contour myself?

谢谢！

import matplotlib.pyplot as plt

fig = plt.figure()
ax = fig.add_subplot(1, 1, 1)
polygon = plt.Polygon([(0,0.6),(1,2),(2,0.4)], True)
circle=plt.Circle((0,0),1.0,facecolor='None', edgecolor='black')
ax.add_patch(polygon)
ax.add_patch(circle)

plt.show()

推荐答案

如果您捕获多边形的添加补丁，您可以使用 set_clip_path 属性.给出您的示例:

You can use the set_clip_path property if you capture the added patch of the polygon. Given your example:

fig = plt.figure()
ax = fig.add_subplot(1, 1, 1)

polygon = plt.Polygon([(0,0.6),(1,2),(2,0.4)], True)
circle = plt.Circle((0,0),1.0,facecolor='None', edgecolor='black')

patch_poly = ax.add_patch(polygon)    
ax.add_patch(circle)

patch_poly.set_clip_path(circle)

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