Matplotlib 绘制虚线圆圈 [英] Matplotlib Plot Dashed Circles
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问题描述
鉴于以下内容:
将matplotlib.pyplot导入为plt将numpy导入为npx = np.random.randn(60)y = np.random.randn(60)x2 = np.random.randn(60)y2 = np.random.randn(60)plt.scatter(x,y,s = 80,facecolors ='none',edgecolors ='r')plt.scatter(x2,y2,s = 80,facecolors ='none',edgecolors ='r')plt.show()
我将如何仅针对 x 2 和 y2 用虚线圆圈绘制相同的数据(其中每个圆圈的轮廓是虚线而不是实线)?
提前致谢!
更新:我知道可以使用
对于该标记大小,我宁愿使用 linestyle =':'
.
Given the following:
import matplotlib.pyplot as plt
import numpy as np
x = np.random.randn(60)
y = np.random.randn(60)
x2 = np.random.randn(60)
y2 = np.random.randn(60)
plt.scatter(x, y, s=80, facecolors='none', edgecolors='r')
plt.scatter(x2, y2, s=80, facecolors='none', edgecolors='r')
plt.show()
How would I plot this same data with dashed circles instead (where the outline of each circle is dashed instead of solid) for x 2 and y2 only?
Thanks in advance!
Update: I know this can be done with patches as in here, but I need it to be done via plt.scatter if possible because I will also be plotting another set of circles on the same plot and using patches messed with the chart dimensions (was way too thin).
解决方案
Pass linestyle='--'
to scatter
.
plt.scatter(x, y, s=80, facecolors='none', edgecolors='r')
plt.scatter(x2, y2, s=80, facecolors='none', edgecolors='r',
linestyle='--')
For that marker size I would rather use linestyle=':'
though.
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