删除直方图中阈值以上的数据 [英] Remove data above threshold in histogram

问题描述

我将数据显示在带有以下代码的直方图中:角度=数据[列[3]]

I have data displayed in a hitogram with the following code: angles = data[columns[3]]

num_bins = 23
avg_samples_per_bin = 200

# len(data['steering'])/num_bins
hist, bins = np.histogram(data['steering'], num_bins)
width = 0.7 * (bins[1] - bins[0])
center = (bins[:-1] + bins[1:]) * 0.5
plt.bar(center, hist, align='center', width=width)
plt.plot((np.min(angles), np.max(angles)), (avg_samples_per_bin, avg_samples_per_bin), 'k-')

显示以下内容:

我正在寻找一个将删除行上方所有数据的函数.或者说，每个bin中的数据不能超过200个.

I'm looking for a function that will delete all data above the line. or in other words, the data in each bin cannot exceed 200.

有没有一种巧妙的方法来做到这一点?

Is there a neat way of doing this?

推荐答案

您可以选择低于特定阈值的值来屏蔽数组.例如:

You can mask your arrays choosing values below a certain threshold. For example:

import numpy as np
import matplotlib.pyplot as plt

fig, (ax1, ax2) = plt.subplots(1,2)
ax1.set_title("Some data")
ax2.set_title("Masked data < 80")

np.random.seed(10)
data = np.random.randn(1000)

num_bins = 23
avg_samples_per_bin = 200

hist, bins = np.histogram(data, num_bins)
width = 0.7 * (bins[1] - bins[0])
center = (bins[:-1] + bins[1:]) * 0.5
ax1.bar(center, hist, align='center', width=width)

threshold = 80
mask = hist < threshold

new_center = center[mask]
new_hist = hist[mask]

ax2.bar(new_center, new_hist, align="center", width=width)

plt.show()

哪个给:

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