在 VScode maven 项目中创建 servlet [英] Create a servlet in VScode maven project

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本文介绍了在 VScode maven 项目中创建 servlet的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在 VScode 中创建了一个 maven-archetype-webapp,并在 src/main/中创建了一个文件夹 Servlets.此文件夹 Servlets 包含 servlet.而且我还添加了 tomcat 服务器,但是当我尝试运行此服务器时出现错误 -[Tomcat 9.0]: 'C:\Program' 不是内部或外部命令,可运行的程序或批处理文件不断出现在控制台上.

I have created a maven-archetype-webapp in VScode and created a folder Servlets in src/main/. This folder Servlets contain servlets. And I have also added tomcat server but when I am trying to run this server error - [Tomcat 9.0]: 'C:\Program' is not recognized as an internal or external command, operable program or batch file is keep coming on console.

此外,当我尝试使用 tomcat 服务器运行项目时,它显示 - 此文件夹不是有效的 web 应用程序

Also when I try to run the project with tomcat server it is showing - this folder is not a valid webapp

[![这是我项目的树结构][1]][1][1]:https://i.stack.imgur.com/YPV3K.png

[![It is the tree structure of my project][1]][1] [1]: https://i.stack.imgur.com/YPV3K.png

FirstServlet.java 代码 -

Code of FirstServlet.java -

import javax.servlet.http.HttpServlet;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.*;
import javax.servlet.http.*;

public class FirstServlet extends HttpServlet{
    public void doGet(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException  {
        
        System.out.println("this is get method....");
        res.setContentType("text/html");
        PrintWriter out = res.getWriter();
        out.println("<h1> this is get method of servlet</h2>");
        
        
    }

}

这是我的 web.xml 文件 -

This is my web.xml file -

<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN" "http://java.sun.com/dtd/web-app_2_3.dtd">

<web-app>
  <display-name>Archetype Created Web Application</display-name>

  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>


  <servlet>
    <servlet-name>first</servlet-name>
    <servlet-class>FirstServlet</servlet-class>
  </servlet>

  <servlet-mapping>
    <servlet-name>first</servlet-name>
    <url-pattern>/first</url-pattern>
  </servlet-mapping>

</web-app>

在此文件中,web-app 标签显示一条带有错误消息的红线 -web-app 元素是 Web 应用程序部署描述符的根.

In this file, web-app tag is showing a red line with error message - The web-app element is the root of the deployment descriptor for a web application.

来源:web-app_2_3.dtd

Source: web-app_2_3.dtd

元素类型web-app"的内容必须匹配 "(icon?,display-name?,description?,distributable?,context-param*,filter*,filter-mapping*,listener*,servlet*,servlet-mapping*,session-config?,mime-映射*,欢迎文件列表?,错误页面*,taglib*,resource-env-ref*,resource-ref*,security-constraint*,login-config?,security-role*,env-entry*,ejb-ref*,ejb-local-ref*)".xml(MSG_CONTENT_INVALID)

The content of element type "web-app" must match "(icon?,display-name?,description?,distributable?,context-param*,filter*,filter-mapping*,listener*,servlet*,servlet-mapping*,session-config?,mime-mapping*,welcome-file-list?,error-page*,taglib*,resource-env-ref*,resource-ref*,security-constraint*,login-config?,security-role*,env-entry*,ejb-ref*,ejb-local-ref*)".xml(MSG_CONTENT_INVALID)

推荐答案

Java:创建 Java 项目 --->Maven ---> ma​​ven-archetype-webapp:

这篇关于在 VScode maven 项目中创建 servlet的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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