在 N & 将两个字符串合并在一起X [英] Merge Two strings Together at N & X

问题描述

我目前混合了 Stringgs 和整数，我试图找出在 N 处将每个字符串的值合并在一起的方法

I've currently got a mixture of Stringgs and integers which i am trying to figure out the method to merge the values of each string together at N

这是我得到的三个字符串/整数:

Here is the three strings/intergers i've got:

加密字符串:npQvFBdZQ4jD6bhAgekjPQ==

EncryptedString: npQvFBdZQ4jD6bhAgekjPQ==

IV: Þá]ÕVâ×,娽kÜVü

IV: Þá]ÕVâ×,娽kÜVü

哈希:7

因此，一旦合并，字符串将是:长度为 41 个字符.

So, once merged the string would be: 41 characters in length.

预期结果大致如下:

7nÞpáq]vÕFVBâd×Z,qå4¨j½Dk6ÜbVhüAgekjPQ==

7nÞpáq]vÕFVBâd×Z,qå4¨j½Dk6ÜbVhüAgekjPQ==

所以，Hash 在数组的开头，EncryptedString 的 peices 是每个偶数迭代(2,4,6,8).IV 将出现在每个奇数上(不包括 1 [So, 3,5,7,9]).直到到达 IV 的末尾，因此 EncryptedString 的剩余部分将附加到字符串的末尾.

So, Hash is at the beginning of the array, peices of EncryptedString is every even iteration (2,4,6,8).. IV would be on every odd occourance (excluding 1 [So, 3,5,7,9]). Until the end of IV has been reached, so then the remainding of EncryptedString would be appended to the end of the string.

这是一个合乎逻辑的头脑螺丝，我对如何执行这样的事情的迭代感到困惑

this is a logical mind screw and i'm stumped on the iterations on how to perform such a thing

所以，简化:在 N 和 X 处合并字符串.

So, simplified: Merge strings together at N and X.

N 是偶数

X 为奇数(不包括第一个)

X Being odd (excluding the first)

推荐答案

我想出了这个结果.不完全是最优雅的，但它的作用就像一个魅力:

I have come up with this result. Not exactly the most elegant, but it works like a charm:

function String_Merge($Array){

    $Encrypted_String = $Array['EncryptedString'];
    $IV = $Array['IV'];
    $Hash = $Array['Hash'];
    $EncStr_Arr = str_split($Encrypted_String);

    $Count = strlen($IV);
    $Increment = 0;
    $String = "";
    $String .= $Hash;
    While ($Increment < $Count){
        $String .= $IV[$Increment];
        $String .= $Encrypted_String[$Increment];
        unset($EncStr_Arr[$Increment]);
        $Increment++;
    }
    $Encrypted_String = implode("",$EncStr_Arr);
    return $String.$Encrypted_String;

}

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