在方法之后更改变量值 [英] Changing variable values after method

问题描述

感谢您过去帮助解决多个编码问题，但我又偶然发现了一个.我真的需要一些指导.

thank you for helping with multiple coding issues in the past but I've stumbled onto one more. I really need some directions on this.

在下面的脚本中，我试图在 Main 函数中调用 met1、met2 和 met3 时更改 b 的值.

In the script below, I am trying to change the value of b when met1, met2 and met3 are called in the Main function.

    class Class3
{
    public class Storage
    {
        public static int a = 100;
        public static int b = a + 5;
    }
public static void Main()
    {
        Methods Test = new Methods();
        Console.WriteLine("Original a value: {0}", Storage.a);
        Console.WriteLine("b value: {0}", Storage.b);
        Test.Met1();
        Console.WriteLine("After met1: {0}", Storage.a);
        Console.WriteLine("b value: {0}", Storage.b);
        Test.Met2();
        Console.WriteLine("After met2: {0}", Storage.a);
        Console.WriteLine("b value: {0}", Storage.b);
        Test.Met3();
        Console.WriteLine("After met3: {0}", Storage.a);
        Console.WriteLine("b value: {0}", Storage.b);
    }
    public class Methods
    {
        public void Met1()
        {
            Storage.a -= 10;
        }
        public void Met2()
        {
            Storage.a -= 10;
        }
        public void Met3()
        {
            Console.WriteLine("{0}", Storage.a);
            Met1();
            Met2();
            if (Storage.a > 10)
            {
                Met3();
            }
        }
    }
}

根据我上面的代码，即使 a 的值发生变化，b 的值仍保持在 105.据我所知，变量 b 没有被再次调用来改变它的值.

From my code above, the value of b stays at 105 even though the value of a changes. From what I can tell from here, variable b was not called again to change its value.

我应该将变量 b 作为方法并调用它吗?这只是我做的一个例子，我有超过 50 个公式，只要公式中的一个变量发生变化，就需要更改这些公式.我不认为创建 50 多个方法是个好主意，因为应该有更好的编码方式.

Should I put variable b as a method and call it? This is just an example I did and I have over 50 formulas that require changes whenever one of the variables within the formula changes. I dont think creating 50 over methods is a good idea as there should be a better way of coding this.

谢谢！

推荐答案

字段不会自动更改.这意味着b = a + 5会将b设置为105.每次重新计算b的值，你可以改变它到一个属性:

Fields don't change automatically. That means that b = a + 5 will set b to 105. To re-calculate the value of b every time, you can change it to a property like:

public static int b => a + 5;

这样每次访问 b 时都会计算 a + 5.

This way every time you access b it calculates a + 5.

这篇关于在方法之后更改变量值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！