在某些情况下如何告诉 mock 调用原始方法? [英] How do I tell mock to call the original method under certain circumstances?

问题描述

我有一个课程想在稍后的测试中模拟:

I have a class that would want to mock later in a test:

class Original {
  function calculate($a) { ... }
}

测试中:

$mock = $this->getMock('Original',['calculate']);
$mock->expcets($this->any())
     ->will($this->returnValueMap([ 
      [1,'ABC'],
      [2,'BCD']
      // somehow tell $mock to call the original calculate() here
);

我想告诉 $mock 在某些条件下回退到原始的 calculate()，例如，如果参数与任何提供的检查不匹配.正如我从阅读 PhpUnit 代码中了解到的，如果未找到匹配项，调用程序只会返回 null :-?

I want to tell $mock to fall back to the original calculate() under certain conditions, for example if arguments do not match any of provided checks. As I understand from reading PhpUnit code the invoker just returns null if no match is found :-?

推荐答案

$mock = $this->getMockBuilder(Original::class)
            ->setMethodsExcept(['calculate'])->disableOriginalConstructor()
            ->getMock();

这将调用原始的 calculate 函数，无论如何.

This will call the original calculate function, no matter what.

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