Mockito - 在空安全迁移后存根一个方法 [英] Mockito - stub a method after the null-safety migration

问题描述

在空安全之前，我可以简单地模拟 sendRequest(...) 方法:

Before the null safety I could simply mock up the sendRequest(...) method like that:

 void stubBaseRepositorySendRequestResponse(String response) {
    when(baseRepository.sendRequest(onGetData: anyNamed('onGetData')))
        .thenAnswer((_) {
      return Future<String>.value(response);
    });
  }

这个方法的签名在哪里:

where the signature of this method is:

Future<T> sendRequest<T>({required Future<T> Function() onGetData})

如何使用新的空安全版本的 mockito 做到这一点?我还能保持这个存根的通用特性并允许传入任何参数吗?

How can this be done with the new null-safe version of mockito? Can I still maintain the generic character of this stub and allow for any arguments to be passed in?

推荐答案

这可以通过 mocktail.更容易，没有 mockito 所需的代码生成.

This can be easily done with mocktail. A lot easier, without the code gen required by mockito.

先导入mocktail很重要:

Important to import mocktail first:

import 'package:mocktail/mocktail.dart';

然后创建一个我们想要模拟的类的模拟:

then create a mock of the class that we want to mock:

class MockBaseRepository extends Mock implements BaseRepository {}

void stubBaseRepositorySendRequestResponse(String response) {
when(() => baseRepository.sendRequest(
        onGetData: any(named: 'onGetData', that: isNotNull))).thenAnswer((_) {
      return Future<String>.value(response);
    });
  }

这篇关于Mockito - 在空安全迁移后存根一个方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！