试图从模数中得到余数但有一些麻烦 - 在 C 中 [英] Trying to get the remainder from modulus but having some troubles - in C

问题描述

使用创建的模数函数进行更新.然而，当它编译时，输入两个数字后，它什么也不返回.

Updated with a created modulus function. However, while it does compile, after entering two numbers, it returns nothing.

#include<stdio.h>
int main(){
    double num1, num2, num3;
    printf("Enter two double numbers > ");
    scanf("%lf", &num1);
    scanf("%lf", &num2);
    num3 = num2;
    while (num3 > num1) {
        if (num3 > num1) {
        num3 = num3-num1;
        }
        else {
            printf("%.4lf float modulo %.4lf is %.4lf", num1, num2, num3);
        }
    }
    return 0; 
}

推荐答案

如您所知，除法实际上只是减法的一种快捷形式，余数是除法时剩下的数字部分.因此，请考虑从 num1 中反复减去 num2，直到得到一个小于 num2 的数字.那是你的模数.我会把代码留给你.

As you know, division is really just a shortcut form of subtraction, and a remainder is the part of the number that is left over when you divide. So consider repeatedly subtracting num2 from num1 until you have a number that is less than num2. That's your modulus. I'll leave the code up to you.

示例:7 % 3:

7 - 3 = 4
4 - 3 = 1

1 < 3, so 7 % 3 = 1

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