通过值/引用传递,是什么? [英] Pass by value/reference, what?

查看:145
本文介绍了通过值/引用传递,是什么?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

该计划为6作为输出,但是当我取消对9号线,输出为5.为什么?我觉得b.a不应该改变,应该主要保持5。

  1级C1 {
2 INT 1 = 5;3公共静态无效的主要(字符串ARGS []){
4 C1 B =新C1();
5 M1(B);
6的System.out.println(b.a);
7}8静态无效M1(C1 C){
9 // C = C1新();
10 C.A = 6;
11}
12}


解决方案

当您在Java传递对象时,将会在由标记为B 引用意味着对象传递方法和 C 作为参数的方法 M1 ,它们都指向同一个对象,因此,当您将值更改为6它就会体现在方法。

当你尝试做

现在 C =新C1(); 然后你做 C 来指向一个不同的对象,但 b 仍然指向你在你的方法创建的对象,因此更新值6不可见的主要方法,你会得到5。

This program gives 6 as output, but when I uncomment the line 9, output is 5. Why? I think b.a shouldn't change, should remain 5 in main.

1  class C1{
2      int a=5;

3      public static void main(String args[]){
4          C1 b=new C1();
5          m1(b);
6          System.out.println(b.a);
7      }

8      static void m1(C1 c){
9          //c=new C1();
10         c.a=6;
11    }
12 }

解决方案

When you pass object in Java they are passed as reference meaning object referenced by b in main method and c as argument in method m1, they both point to the same object, hence when you change the value to 6 it gets reflected in main method.

Now when you try to do c = new C1(); then you made c to point to a different object but b is still pointing to the object which you created in your main method hence the updated value 6 is not visible in main method and you get 5.

这篇关于通过值/引用传递,是什么?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆