COM pression和DECOM $ P $用Java参数字符串的pssion [英] Compression and Decompression of Argument Strings in Java

问题描述

我有想出办法太DECOM preSS Java中的字符串的麻烦。这是一个基本的Java类，我正在所以只需要基本的命令，没有什么太花哨。它的目标是能够键入

  C：\\＆GT;的Java的COM preSS -c aaaabbbbbcc
 

在命令提示符，然后将打印 a4b5c2 （如它为com preSS参数字符串）。

另一个目的是键入

  C：\\＆GT;的Java的COM preSS -d a5b7c4
 

和将打印 aaaaabbbbbbbcccc （像它会DECOM preSS参数字符串）。在DECOM pression是我遇到的问题。这里是我的code，任何帮助，我得到的是多少AP preciated。

 进口的java.util。*;公共类的COM $ P $ {PSS
    公共静态无效的主要（字符串ARGS []）{        扫描程序扫描=新的扫描仪（System.in）;
        串originalString = scan.nextLine（）;
        INT数= scan.nextInt（）;        如果（参数[0] .equals（ -  C））{
            的System.out.println（COM preSS）;
            COM preSS（originalString）;
        }        否则，如果（参数[0] .equals（ -  D））{
            的System.out.println（DECOM preSS）;
            DECOM preSS（originalString）;
        }其他{
            的System.out.println（的COM preSS由凯尔西等待区域方案）;
            的System.out.println（用法：JAVA的COM preSS [-c，-d] LT; INPUTFILE＆GT; OUTPUTFILE）;
        }
    }    公共静态无效COM preSS（字符串originalString）{
        诠释计数= 0;
        焦补偿= originalString.charAt（0）;
        的for（int i = 0; I＆LT; originalString.length（）;我++）{
            originalString.charAt（ⅰ）;            如果（补偿== originalString.charAt（I））
                算上++;
            其他{
                System.out.print（补偿++计数）;
                排版= originalString.charAt（ⅰ）;
                数= 1;
            }
        }
        的System.out.println（补偿++计数）;
    }    公共静态无效DECOM preSS（字符串originalString）{    }
}
 

解决方案

 快速code为你..
公共静态无效DECOM preSS（字符串originalString）
{
        StringBuffer的finalString =新的StringBuffer（）;;
        焦炭previouschar = originalString.charAt（0）;
        的for（int i = 1; I＆LT; originalString.length（）; I + = 2）{
                为（中间体J = 0; J＆下;的Integer.parseInt（+ originalString.charAt（ⅰ））; J ++）{
                    finalString.append（previouschar）;
                }
                如果第（i + 1＆下; originalString.length（））
                {
                    previouschar = originalString.charAt第（i + 1）;
                }
        }
        的System.out.println（finalString.toString（））;
}
 

I'm having trouble coming up with a way too decompress a String in Java. This is a basic Java class I'm taking so it only requires basic commands, nothing too fancy. The objective it to able to type

C:\>java Compress -c aaaabbbbbcc

in the command prompt and it will print a4b5c2 (like it is compress the argument string).

The other objective is to type

C:\>java Compress -d a5b7c4

and it will print aaaaabbbbbbbcccc (like it will decompress the argument String). The decompression is the issue I'm having. Here is my code, any help I get is much appreciated.

import java.util.*;

public class Compress {
    public static void main(String args[]) {

        Scanner scan = new Scanner(System.in);
        String originalString = scan.nextLine();
        int number = scan.nextInt();

        if (args[0].equals("-c")) {
            System.out.println("compress");
            compress(originalString);
        }

        else if (args[0].equals("-d")) {
            System.out.println("decompress");
            decompress(originalString);
        } else {
            System.out.println("Compress program by Kelsey Faram");
            System.out.println("usage: java Compress [-c,-d] < inputFile > outputFile");
        }
    }

    public static void compress(String originalString) {
        int count = 0;
        char comp = originalString.charAt(0);
        for (int i = 0; i < originalString.length(); i++) {
            originalString.charAt(i);

            if (comp == originalString.charAt(i))
                count++;
            else {
                System.out.print(comp + "" + count);
                comp = originalString.charAt(i);
                count = 1;
            }
        }
        System.out.println(comp + "" + count);
    }

    public static void decompress(String originalString) {

    }
}

解决方案

Quick Code for you..


public static void decompress(String originalString)
{
        StringBuffer finalString = new StringBuffer();;
        char previouschar = originalString.charAt(0);
        for(int i=1; i < originalString.length(); i+=2){
                for(int j = 0 ; j< Integer.parseInt(""+originalString.charAt(i));j++) {
                    finalString.append(previouschar);
                }               
                if(i+1 < originalString.length())
                {
                    previouschar=originalString.charAt(i+1);
                }
        }
        System.out.println(finalString.toString());
}

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