不能管理使用Python中的子模块（没有这样的文件） [英] Can't manage to use subprocess module in Python (no such file)

问题描述

我想在我的蟒蛇code启动一个bash脚本。
假设该文件containting的bash脚本被称为/home/myname/myfile.sh，我已经试过：

I'm trying to launch a bash script in my python code. Assuming the file containting the bash script is called "/home/myname/myfile.sh", I've tried :

import subprocess
subprocess.call(['/home/myname/myfile.sh'])

但我得到：

Traceback (most recent call last):
  File "run_splitseq.py", line 21, in <module>
    subprocess.call(["/home/myname/myfile.sh"])
  File "/home/myname/.pythonbrew/pythons/Python-2.6.5/lib/python2.6/subprocess.py", line 480, in call
    return Popen(*popenargs, **kwargs).wait()
  File "/home/myname/.pythonbrew/pythons/Python-2.6.5/lib/python2.6/subprocess.py", line 633, in __init__
    errread, errwrite)
  File "/home/myname/.pythonbrew/pythons/Python-2.6.5/lib/python2.6/subprocess.py", line 1139, in _execute_child
    raise child_exception
OSError: [Errno 2] No such file or directory

当我尝试：

subprocess.call(['/home/myname/myfile.sh'], shell=True)

我得到：

/bin/sh: 1: /home/myname/myfile.sh: not found

Whatsmore我喜欢把争论，在网上搜索，我发现这种方式：

Whatsmore I'd like to put arguments, searching on the net I've found this way :

subprocess.call(['/home/myname/myfile.sh', arg1], shell=True)

但它仍然因为我得到不工作：

But it still doesn't work since I get :

arg1: 1: arg1: /home/myname/myfile.sh: not found

谁能帮帮我吗？ ：）

Can anyone please help me ? :)

推荐答案

我不知道是什么原因导致你的问题。不过，我已经看到了一些东西，我很担心：

I'm not sure what causes your problem. But I've seen some things I'm concerned about:

1. 到 subprocess.call（）你应该给任何字符串列表，第一个是可执行文件的路径，其余单身的参数;那么你应该使用壳=假（或者忽略它，因为这是默认的）。的或者的你一起壳= TRUE 通过，那么你应该通过只有一个字符串（而不是一个字符串列表！），这将是间preTED并通过外壳裂开，所以它应该包含可执行文件路径和所有参数（中引用的版本，如果需要的话）。

1. to subprocess.call() you should give either a list of strings, the first being the path to the executable and the remaining being single arguments; then you should use shell=False (or omit it as this is the default). Or you pass along shell=True, then you should pass exactly one string (not a list of strings!) which will be interpreted and split by a shell, so it should contain the path to the executable and all arguments (in quoted versions, if necessary).

所以它要么

subprocess.call（['/路径/要/可执行文件，ARG1，ARG2']）＃SHELL =假

或

subprocess.call（'/路径/要/可执行文件ARG1ARG2'，壳=真）

错误消息未找到可由于多种原因而发生。

The error message not found can occur because of several reasons.

一个。 （;没有尝试壳= TRUE 与字符串列表，例如）

a. Wrong way of specifying the path to the executable (shell=True with list of string, for instance; didn't try that).

乙。可执行文件本身不存在（但你检查，你说的）。

b. The executable itself does not exist (but you checked for that you said).

℃。可执行文件不能运行（权限位丢失）。

c. The executable isn't executable (permission bits missing).

Ð。该可执行文件在其第一行指定一个跨preTER（使用＃！），这不存在（如＃！/ bin / sh的或类似）。

d. The executable specifies in its first line an interpreter (using #!) which does not exist (e. g. #!/bin/sh or similar).

有没有任何这些申请？

这篇关于不能管理使用Python中的子模块（没有这样的文件）的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！