MS 访问加密存储在用户表中的用户密码 (SQL) [英] MS access Encrypt Users Passwords Stored in User Table (SQL)

问题描述

我的数据库是链接到 SQL 表的 Access 前端，有没有办法加密/散列存储在我的用户表中的密码?

My database is Access front end which is linked to SQL tables, is there a way of Encrypting/Hashing the passwords that are stored in my user table?

我看过有关 Hashbytes 和 Salt 的内容吗?但不确定如何实施?

I have seen something about Hashbytes and Salt? but not sure how to implement it?

预先感谢您的帮助

推荐答案

在 Access 中没有本地加密/解密方法，但创建自己的方法并不难.您可以使用旧的Zebras"方法，为字母表分配不同的字母(您也可以使用一些数字或其他 ASCII 字符代替):

There is no native way to encrypt/decrypt in Access, but it's not hard to create your own. You can use the old "Zebras" method, by assigning different letters to the alphabet (you could also use some numbers or other ASCII characters instead):

Public Function Encrypt(strvalue As String) As String

Const LowerAlpha    As String = "abcdefghijklmnopqrstuvwxyz"
Const LowerSub      As String = "zebrascdfghijklmnopqtuvwxy" 'zebras
Const UpperAlpha    As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
Const UpperSub      As String = "ZEBRASCDFGHIJKLMNOPQTUVWXY" 'ZEBRAS

Dim lngi            As Long
Dim lngE            As Long
Dim strEncrypt      As String
Dim strLetter       As String

If strvalue & "" = "" Then Exit Function

For lngi = 1 To Len(strvalue)

    strLetter = Mid(strvalue, lngi, 1)

    Select Case Asc(strLetter)

        Case 65 To 90 'Uppercase
            'Find position in alpha string
            For lngE = 1 To Len(UpperAlpha)
                If Mid(UpperAlpha, lngE, 1) = strLetter Then GoTo USub
            Next
USub:
            strEncrypt = strEncrypt & Mid(UpperSub, lngE, 1)

        Case 97 To 122 'Lowercase
            'Find position in alpha string
            For lngE = 1 To Len(LowerAlpha)
                If Mid(LowerAlpha, lngE, 1) = strLetter Then GoTo LSub
            Next
LSub:
            strEncrypt = strEncrypt & Mid(LowerSub, lngE, 1)

        Case Else 'Do not substitute

            strEncrypt = strEncrypt & strLetter

    End Select

Next

'Now pass this string through ROT13 for another tier of security

For lngi = 1 To Len(strEncrypt)
    Encrypt = Encrypt & Chr(Asc(Mid(strEncrypt, lngi, 1)) + 13)
Next

End Function

然后反向解密:

Public Function Decrypt(strvalue As String) As String

Const LowerAlpha    As String = "abcdefghijklmnopqrstuvwxyz"
Const LowerSub      As String = "zebrascdfghijklmnopqtuvwxy" 'zebras
Const UpperAlpha    As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
Const UpperSub      As String = "ZEBRASCDFGHIJKLMNOPQTUVWXY" 'ZEBRAS

Dim lngi            As Long
Dim lngE            As Long
Dim strDecrypt      As String
Dim strLetter       As String

If strvalue & "" = "" Then Exit Function

'Reverse the ROT13 cipher

For lngi = 1 To Len(strvalue)
    strDecrypt = strDecrypt & Chr(Asc(Mid(strvalue, lngi, 1)) - 13)
Next

'Now reverse the encryption

For lngi = 1 To Len(strDecrypt)

    strLetter = Mid(strDecrypt, lngi, 1)

    Select Case Asc(strLetter)

        Case 65 To 90 'Uppercase
            'Find position in sub string
            For lngE = 1 To Len(UpperSub)
                If Mid(UpperSub, lngE, 1) = strLetter Then GoTo USub
            Next
USub:
            Decrypt = Decrypt & Mid(UpperAlpha, lngE, 1)

        Case 97 To 122 'Lowercase
            'Find position in sub string
            For lngE = 1 To Len(LowerSub)
                If Mid(LowerSub, lngE, 1) = strLetter Then GoTo LSub
            Next
LSub:
            Decrypt = Decrypt & Mid(LowerAlpha, lngE, 1)

        Case Else 'Do not substitute

            Decrypt = Decrypt & strLetter

    End Select

Next

End Function

这篇关于MS 访问加密存储在用户表中的用户密码 (SQL)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！