在二维数组中表示索引的更简单方法 [英] Easier way to represent indicies in a 2D array

问题描述

我是编程新手，我已经创建了一个简单的井字游戏.它接受了二维数组的行和列的输入.但是，我想让它更简单，而是使用 1-9 的值来表示板上的每个方块.

I'm new to programming and I've created a simple tic-tac-toe game. It took an input of the row and column of a 2d array. However, I want to make it simpler and use a value of 1-9 instead to represent each square on the board.

我的方法似乎相当漫长和复杂.因为我想节省空间，所以很抱歉格式不正确.

The way I've gone about this seems rather long and complex. Sorry about the bad formatting since I wanted to save space.

if (pos >= 0 && pos <= 9) { //checks if number is a valid position on the board
    if (pos == 1 && board[0][0] == ' ') { board[0][0] = xo; return true; }
    if (pos == 2 && board[0][1] == ' ') { board[0][1] = xo; return true; }
    if (pos == 3 && board[0][2] == ' ') { board[0][2] = xo; return true; }
    if (pos == 4 && board[1][0] == ' ') { board[1][0] = xo; return true; }
    if (pos == 5 && board[1][1] == ' ') { board[1][1] = xo; return true; }
    if (pos == 6 && board[1][2] == ' ') { board[1][2] = xo; return true; }
    if (pos == 7 && board[2][0] == ' ') { board[2][0] = xo; return true; }
    if (pos == 8 && board[2][1] == ' ') { board[2][1] = xo; return true; }
    if (pos == 9 && board[2][2] == ' ') { board[2][2] = xo; return true; }
}
return false;

内部 if 语句检查索引是否为空，然后根据输入的数字分配 x 或 o.如果有人知道这样做的任何更清洁"和更简单的方法，将不胜感激.

The inner if statements check if the index is empty and then assigns the x or o depending on the number entered. If anyone knows any 'cleaner' and easier ways of doing this it would be much appreciated.

推荐答案

赋值、算术和一元运算符

• / - 除法运算符
• % - 余数运算符

• / - Division operator
• % - Remainder operator

你可以在没有循环的情况下获得单元格[i][j]的坐标，只使用1<范围内的一个变量pos/code> 到 9:

You can get the coordinates of the cell [i][j] without loops at all, using only one variable pos in the range from 1 to 9:

public static boolean isValid(int pos, char xo) {
    int i = (pos - 1) / 3; // row
    int j = (pos - 1) % 3; // column
    if (board[i][j] == ' ') {
        board[i][j] = xo;
        return true;
    }
    return false;
}

这篇关于在二维数组中表示索引的更简单方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！