返回嵌套数组的所有键 [英] return all keys of nested array

问题描述

给定一个这样的任意深度的嵌套数组:

given a nested array of arbitrary depth like this:

$array = array(
            1400=> 
                array(7300=>
                        array(
                            7301=> array(),
                            7302=> array(),
                            7305=> array(
                                7306=>array()
                            ),
                        ),
                    7314=>array()
                ),
            );

如何获得任意键的键层次结构.

how would one get the hierarchy of keys for any key.

例如:

getkeys(7305);

getkeys(7305);

应按该顺序返回 1400,7300,7305

should return 1400,7300,7305 in that order

或

getkeys(7314);

getkeys(7314);

应该返回 1400,7314

should return 1400,7314

所有数组键都是唯一值

推荐答案

使用 RecursiveIteratorIterator

$array = array(
  1400 => array(
    7300 => array(
      7301=> array(),
      7302 => array(),
      7305 => array(
        7306=>array()
      ),
    ),
    7314=>array()
  ),
);

function getKeys($key, $array) {
  $found_path = [];
  $ritit = new RecursiveIteratorIterator(new RecursiveArrayIterator($array), RecursiveIteratorIterator::SELF_FIRST);

  foreach ($ritit as $leafValue) {

    $path = array();
    foreach (range(0, $ritit->getDepth()) as $depth) {
      $path[] = $ritit->getSubIterator($depth)->key();
    }

    if (end($path) == $key) {
      $found_path = $path;
      break;
    }
  }

  return $found_path;
}

print_r(getKeys(7305, $array));
// Array
// (
//     [0] => 1400
//     [1] => 7300
//     [2] => 7305
// )

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