在pyqt5/python 3中关闭主GUI窗口时如何关闭子线程? [英] How to get a child thread to close when main GUI window is closed in pyqt5 / python 3?

问题描述

我正在使用 pyqt5 (Python 3.6) 编写 GUI.我正在尝试与主 GUI 并行运行另一个线程.当我关闭主应用程序时，我希望这个子线程终止.在这个例子中，子线程是一个简单的计数器.当我关闭主 GUI 时，计数器仍然继续运行.当 GUI 窗口关闭时，如何让线程结束?在实际情况下，我可能有一个线程正在运行需要几分钟才能执行的操作.我不愿意在线程中使用标志来评估它是否应该结束，因为在 GUI 窗口关闭后线程可能需要几分钟才能关闭.我希望线程立即结束.有什么建议么?谢谢.

I am writing a GUI using pyqt5 (Python 3.6). I am trying to run another thread in parallel of the main GUI. I would like this child thread to terminate when I close the main application. In this example, the child thread is a simple counter. When I close the main GUI, the counter still keeps going. How can I get the thread to end when the GUI window is closed? In the real case I may have a thread that is running operations that takes a few minutes to execute. I am reluctant to use a flag within the thread to assess if it should end because it may take minutes for the thread to close after the GUI window has been closed. I would prefer the thread to end right away. Any suggestions? Thank you.

from PyQt5 import QtWidgets
from PyQt5.QtWidgets import (QWidget, QApplication,QPushButton, 
                             QVBoxLayout)
import time, threading, sys

class testScriptApp(QtWidgets.QWidget):

    def __init__(self, parent=None):
        # initialize th widget
        QtWidgets.QWidget.__init__(self, parent)
        # set the window title
        self.setWindowTitle("Scripting")
        # manage the layout
        self.mainGrid = QVBoxLayout()
        self.button = QPushButton('Start')
        self.button.clicked.connect(self.on_click)
        self.mainGrid.addWidget(self.button)
        self.setLayout(self.mainGrid)

    def on_click(self):
        self.worker = threading.Thread(target=Worker)
        self.worker.daemon = True
        self.worker.start()

def Worker(count=1):
    while count>0:
        print(count)
        time.sleep(2)
        count+=1

if __name__ == "__main__":
    app = QtWidgets.QApplication(sys.argv)
    myapp = testScriptApp()
    myapp.show()
    app.exec_()

推荐答案

from PyQt5 import QtWidgets
from PyQt5.QtWidgets import (QWidget, QApplication,QPushButton, 
                             QVBoxLayout)
from PyQt5.QtCore import QThread,QObject
import time, threading, sys

class testScriptApp(QtWidgets.QWidget):

    def __init__(self, parent=None):
        # initialize th widget
        QtWidgets.QWidget.__init__(self, parent)
        # set the window title
        self.setWindowTitle("Scripting")
        # manage the layout
        self.mainGrid = QVBoxLayout()
        self.button = QPushButton('Start')
        self.button.clicked.connect(self.on_click)
        self.mainGrid.addWidget(self.button)
        self.setLayout(self.mainGrid)

    def on_click(self):
        self.my_thread = QThread()
        self.worker = Worker()
        self.worker.moveToThread(self.my_thread)
        self.my_thread.started.connect(self.worker.run)
        self.my_thread.start()        

    def closeEvent(self,event):
        print('Closing')

class Worker(QObject):

    def __init__(self):
        super().__init__()

    def run(self):
        count=1
        while count>0:
            print(count)
            time.sleep(2)
            count+=1

if __name__ == "__main__":
    app = QtWidgets.QApplication(sys.argv)
    myapp = testScriptApp()
    myapp.show()
    app.exec_()

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