使用 WHERE IN 返回 NULL [英] Returning NULL using WHERE IN
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问题描述
我正在使用这个查询:
SELECT GROUP_CONCAT(column1) as values FROM archive WHERE column2 IN (21, 22)
查询从 Column2 具有指定值之一的行中返回 Column1 的值.
The query returns the values of Column1 from lines whose Column2 has one of the specified values.
问题是在这种情况下,在表中找不到值 21.所以我需要返回一个NULL.但查询仅返回找到的值.
The problem is that in this case the value 21 is not found in the table. So I need to return a NULL. But the query is only returning the value found.
查询返回:
File 1
我希望:
File 1, NULL
推荐答案
A 右外连接
、左外连接
、case
以及not exists
也可以使用.下面的一些示例...(带有指向 SQL Fiddle 工作示例的链接).
A right outer join
, left outer join
, case
and also not exists
can also be utilized. Some examples below... (with links to SQL Fiddle working examples).
SELECT GROUP_CONCAT(CASE WHEN COLUMN1 IS NULL THEN "NULL" ELSE COLUMN1 END)
FROM archive
RIGHT OUTER JOIN
(SELECT 21 AS id
UNION SELECT 22 AS id) AS tmp ON tmp.id=archive.column2;
SQL 小提琴:http://sqlfiddle.com/#!2/805e1c/9一个>
SELECT GROUP_CONCAT(
CASE WHEN COLUMN1 IS NULL THEN "NULL" ELSE COLUMN1 END)
FROM archive
RIGHT OUTER JOIN temporary tmp ON tmp.id=archive.column2;
SQLFiddle:http://sqlfiddle.com/#!2/36fba/2
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