MySQL $i++ 等价物 [英] MySQL $i++ equivalent
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问题描述
我正在使用的查询:
SELECT COUNT(*),
SUM(amount) AS amount,
FROM_UNIXTIME(added, '%W (%e/%m)') AS daily
FROM affiliates_earnings
WHERE added >= '1319074836'
AND added <= '1319679636'
GROUP BY daily
输出:
+----------+--------+-------------------+
| COUNT(*) | amount | daily |
+----------+--------+-------------------+
| 1 | 195 | Tuesday (25/10) |
| 4 | 470 | Wednesday (26/10) |
+----------+--------+-------------------+
我想显示的内容:
+-------+----------+--------+-------------------+
| i |COUNT(*) | amount | daily |
+-------+----------+--------+-------------------+
| 1 | 1 | 195 | Tuesday (25/10) |
| 2 | 4 | 470 | Wednesday (26/10) |
+-------+----------+--------+-------------------+
本质上 i
将是序列号(即 1,2,3,4,5,6...).
Essentially i
would be the sequential number (i.e. 1,2,3,4,5,6...).
我将如何做到这一点?
推荐答案
没有 ROW_NUMBER(),你可以伪造它 根据这个答案 或 这个:
Without ROW_NUMBER(), you can fake it per this answer or this one:
SELECT @i := @i + 1 AS i, COUNT(*), ...
FROM affiliates_earnings
JOIN (SELECT @i := 0) dummy
WHERE ...
GROUP BY ...;
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