如何使用mysqli准备好的语句? [英] How to use mysqli prepared statements?

问题描述

我正在尝试准备好的语句，但下面的代码不起作用.我收到错误:

I am trying out prepared statements, but the below code is not working. I am getting the error:

致命错误:在非对象上调用成员函数execute()/var/www/prepared.php 第 12 行

Fatal error: Call to a member function execute() on a non-object in /var/www/prepared.php on line 12

<?php

    $mysqli = new mysqli("localhost", "root", "root", "test");
    if ($mysqli->connect_errno) {
        echo "Failed to connect to MySQL: " . $mysqli->connect_error;
    }

    $stmt = $mysqli->prepare("INSERT INTO users (name, age) VALUES (?,?)");

    // insert one row
    $stmt->execute(array('one',1));

    // insert another row with different values
    $stmt->execute(array('two',1));
?>

另外，我是否需要将 mysqli 用于准备好的语句?任何人都可以向我指出一个完整的示例，从连接到插入再到带有错误处理的选择的准备语句?

Also, do I need to use mysqli for prepared statements? Can anyone point me to a complete example on prepared statements from connection to insertion to selection with error handling?

推荐答案

来自 <代码>mysqli::prepare 文档:

From the mysqli::prepare docs:

在执行语句或获取行之前，必须使用 mysqli_stmt_bind_param() 和/或 mysqli_stmt_bind_result() 将参数标记绑定到应用程序变量.

The parameter markers must be bound to application variables using mysqli_stmt_bind_param() and/or mysqli_stmt_bind_result() before executing the statement or fetching rows.

bind_param 文档.

即:

$name = 'one';
$age  = 1;

$stmt = $mysqli->prepare("INSERT INTO users (name, age) VALUES (?,?)");

// bind parameters. I'm guessing 'string' & 'integer', but read documentation.
$stmt->bind_param('si', $name, $age);

// *now* we can execute
$stmt->execute();

这篇关于如何使用mysqli准备好的语句?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！