mysql 表字段 - 资源 ID #7 [英] mysql table fields - Resource id #7

问题描述

我在数据库中有下表:

id, username, email, old_ip, current_ip

每次用户登录时，我都希望他们当前的 ip 存储在 current_ip 中.但在此之前我想保存他们的 old_ip(从上次登录开始)所以我想我可以在将新数据复制到 current_ip 之前将 current_ip 中的内容移动到 old_ip.

Everytime the user logs in, I want their current ip to be stored in current_ip. But before that I want to save their old_ip (from last login) so I thought I could move what is in current_ip to old_ip before copying the new data to current_ip.

我在登录时写了这个脚本:

I wrote this script when logging in:

........
$sql = mysql_query("SELECT * FROM members WHERE email='$email' AND password='$password'"); 
$login_check = mysql_num_rows($sql);
if($login_check > 0){ 
   while($row = mysql_fetch_array($sql)){ 
    // Get member ID into a session variable
    $id = $row["id"];   
    session_register('id'); 
    $_SESSION['id'] = $id;
    // Get member username into a session variable
    $username = $row["username"];   
    session_register('username'); 
    $_SESSION['username'] = $username;


    // IP getting
    $old_ip = mysql_query("SELECT current_ip FROM members WHERE id='$id'");
    $result_old_ip = $old_ip;
    $sql_setoldip = mysql_query("UPDATE members SET old_ip='".$result_old_ip."' WHERE id='$id'");


    $getip = getenv("REMOTE_ADDR");
    $current_ip = $getip;
    // Update ip in database
    mysql_query("UPDATE members SET current_ip='".$current_ip."' WHERE id='$id'");

}

我在 old_ip 字段中得到的结果是Resource id #7" 有什么帮助吗?

The result I get in the old_ip feild is "Resource id #7" Any help please ?

推荐答案

mysql_query() 语句返回一个指向结果集的资源指针，而不是数据本身.您需要使用 mysql_fetch_array() 来检索表中的实际数据.

mysql_query() statement returns a resource pointer to the result set, not the data itself. You'll need to use mysql_fetch_array() in order to retrieve the actual data in the table.

像这样:

$old_ip = mysql_query("SELECT current_ip FROM members WHERE id='$id'");
$row = mysql_fetch_array($old_ip);
$result_old_ip = $row['current_ip'];

这将解决您的问题.

希望这会有所帮助.

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