如何计算超过 1 个有子句 mysql [英] how to count with more than 1 having clause mysql
问题描述
我有一张名为 order_star_member 的表，其中包含 createdAt 作为交易日期，users_id 作为买家，total_price_star_member 作为交易金额.在这种情况下，我想找出拥有明星会员的买家(一个月内的交易 >= 600000)并找出他们来自哪里，order_star_member 的数据(虚拟)从 2019 年 1 月开始到 2019 年 3 月
i have 1 table called order_star_member, which contain createdAt as the date of the transaction, users_id as the buyer, total_price_star_member as the amount of the transaction. on this case i want to find out buyer who had star member (transaction in a month within >= 600000) and find out where they coming from, the data(dummy) for order_star_member begin on January 2019 untill March 2019
CREATE TABLE order_star_member ( users_id INT,
createdAt DATE,
total_price_star_member DECIMAL(10,2) );
INSERT INTO order_star_member VALUES
(12,'2019-01-01',100000),
(12,'2019-01-10',100000),
(12,'2019-01-20',100000),
(12,'2019-02-10',100000),
(12,'2019-02-15',300000),
(12,'2019-02-21',500000),
(13,'2019-01-02',900000),
(13,'2019-01-11',300000),
(13,'2019-01-18',400000),
(13,'2019-02-06',100000),
(13,'2019-02-08',900000),
(13,'2019-02-14',400000),
(14,'2019-01-21',500000),
(14,'2019-01-23',200000),
(14,'2019-01-24',300000),
(14,'2019-02-08',100000),
(14,'2019-02-09',200000),
(14,'2019-02-14',100000),
(15, '2019-03-04',1000000),
(14, '2019-03-04', 300000),
(14, '2019-03-04', 350000),
(13, '2019-03-04', 400000),
(15, '2019-01-23', 620000),
(15, '2019-02-01', 650000),
(12, '2019-03-03', 750000),
(16, '2019-03-04', 650000),
(17, '2019-03-03', 670000),
(18, '2019-02-02', 450000),
(19, '2019-03-03', 750000);
SELECT * from order_star_member;
然后我每月汇总数据
-- summary per-month data
SELECT users_id,
SUM( CASE WHEN MONTHNAME(createdAt) = 'January'
THEN total_price_star_member
END ) total_price_star_member_January,
SUM( CASE WHEN MONTHNAME(createdAt) = 'February'
THEN total_price_star_member
END ) total_price_star_member_February,
SUM( CASE WHEN MONTHNAME(createdAt) = 'March'
THEN total_price_star_member
END ) total_price_star_member_March
FROM order_star_member
GROUP BY users_id
ORDER BY 1;
在这种情况下，我想找出 3 月份每个明星成员(users_id 在一个月内交易 >= 600000)的分布，以及 users_Id 在 3 月之前进行交易的位置 >= 600.000(如果 users_Id 在第一次三月，则users_Id进入三月统计)
on this case i want to find out the distribution for each star member (users_id who transaction >= 600000 in a month) in march and where the users_Id doing his transaction >= 600.000 before march (if the users_Id doing transaction on the first time in march, then the users_Id enter the march to march statistic)
expected results for star member on month march statistics
+-------------------+------+-------+
| count star_member | year | month |
+-------------------+------+-------+
| 2 | 2019 | 1 |
| 1 | 2019 | 2 |
| 3 | 2019 | 3 |
+-------------------+------+-------+
说明:有2个users_Id在3月成为star_member(users_Id 14,15)，并在2019年1月成为他的第一个star_member，有 1 个 users_id 在 3 月成为 star_member (users_id 12) 并在 2019 年 2 月成为他的第一个 star_member，并且有 3 个 users_id 在 3 月成为 star_member (users_id 16, 17, 19) 并在 2019 年 3 月成为他的第一个 star_member
explanation : there's 2 users_Id who become star_member on march (users_Id 14,15) and become his first star_member on january 2019, there's 1 users_id who become star_member on march (users_id 12) and become his first star_member on february 2019, and there's 3 users_id who become star_member on march (users_id 16, 17, 19) and become his first star_member on march 2019
这是我目前的进度语法
select count(osm.users_id) as count_buyer, year(osm.createdAt) as year,
month(osm.createdAt) as month
from order_star_member osm
WHERE osm.createdAt >= MAKEDATE(YEAR(osm.createdAt), 1)
+ INTERVAL month(osm.createdAt) month- INTERVAL 1 month AND
osm.createdAt <= MAKEDATE(YEAR(osm.createdAt), 1)
+ INTERVAL month(osm.createdAt) month- INTERVAL 1 day group by users_Id
having sum(total_price_star_member) >= 600000
AND
NOT EXISTS (SELECT 1 from order_star_member osm2
WHERE osm2.users_id = osm.users_id
AND osm2.createdAt < MAKEDATE(YEAR(osm.createdAt), 1) +
INTERVAL month(osm.createdAt) month - INTERVAL 1 month
group by users_id
having sum(total_price_star_member) >= 600000)
AND
EXISTS (SELECT 1 from order_star_member osm3
where
osm3.users_id = osm.users_id AND
osm3.createdAt >= '2019-03-01' AND
osm3.createdAt < '2019-04-01' group by users_id
having sum(total_price_star_member) >= 600000)
group by year(osm.createdAt), month(osm.createdAt);
这是小提琴https://dbfiddle.uk/?rdbms=mysql_5.7&42900f967d7af9659d8639d7/a>
here's the fiddle https://dbfiddle.uk/?rdbms=mysql_5.7&fiddle=d642774357900f967d7af9659d8639d7
推荐答案
WITH
cte1 AS ( SELECT DISTINCT
users_id,
DATE_FORMAT(createdAt, '%Y%m') year_and_month,
SUM(total_price_star_member) OVER (PARTITION BY users_id, DATE_FORMAT(createdAt, '%Y%m')) month_price
FROM order_star_member ),
cte2 AS ( SELECT users_id, MIN(year_and_month) year_and_month
FROM cte1
WHERE month_price >= 600000
GROUP BY users_id )
SELECT COUNT(users_id) count_star_member,
year_and_month DIV 100 `year`,
year_and_month MOD 100 `month`
FROM cte2
GROUP BY year_and_month
ORDER BY `year`, `month`;
您的 MySQL 服务器版本是什么?– 秋奈
What is your MySQL server version? – Akina
这是 5.7.23-log – Fachry Dzaky Al-Qadri Sabil
it's 5.7.23-log – Fachry Dzaky Al-Qadri Sabil
SELECT COUNT(users_id) count_star_member,
year_and_month DIV 100 `year`,
year_and_month MOD 100 `month`
FROM (SELECT users_id,
MIN(year_and_month) year_and_month
FROM ( SELECT users_id,
DATE_FORMAT(createdAt, '%Y%m') year_and_month,
SUM(total_price_star_member) month_price
FROM order_star_member
GROUP BY users_id,
DATE_FORMAT(createdAt, '%Y%m')
HAVING month_price >= 600000 ) starrings
GROUP BY users_id ) first_starrings
GROUP BY year_and_month
ORDER BY `year`, `month`;
明星会员三月统计的预期结果
expected results for star member on month march statistics
...
嗯... users_id=13 没有被计算在内，因为他没有在三月出演???– 秋奈
Hmm... users_id=13 is NOT counted because he is NOT starred in March??? – Akina
是的，因为我想在 3 月做统计，而 users_id 13 没有被计算在内，因为他们不是 3 月的明星会员(交易 >= 600000)– Fachry Dzaky Al-Qadri Sabil
yes, because i want to make statistic on month march, and users_id 13 not counted because they not being star member on march (transaction >= 600000) – Fachry Dzaky Al-Qadri Sabil
据我所知，统计在此统计信息中的用户必须在本月加星标.如果是这样
As I understand the user counted in this statistic MUST be starred in this month. If so
SELECT COUNT(users_id) count_star_member,
year_and_month DIV 100 `year`,
year_and_month MOD 100 `month`
FROM (SELECT users_id,
MIN(year_and_month) year_and_month
FROM ( SELECT users_id,
DATE_FORMAT(createdAt, '%Y%m') year_and_month,
SUM(total_price_star_member) month_price
FROM order_star_member
GROUP BY users_id,
DATE_FORMAT(createdAt, '%Y%m')
HAVING month_price >= 600000 ) starrings
GROUP BY users_id
HAVING SUM(year_and_month = '201903') > 0 ) first_starrings
GROUP BY year_and_month
ORDER BY `year`, `month`;
这篇关于如何计算超过 1 个有子句 mysql的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
