从mysql表中提取id [英] extracting id's from a mysql table

问题描述

抱歉，这个问题看起来很简单，但我对 php 很陌生，我试图在索引页中显示排名，但我不知道如何从 中的列中提取 id一张桌子，有两张桌子:

sorry for this question it may seem very simple but I'm very new in php, I'm trying to make a ranking appear in the index page, but I don't know how to extract the id's from a column in a table, there's 2 tables:

- raking table -
    city = 'Boston'
    ranking_name = 'the best 5 places'
    business_ids = '67,43,1,6,78'

- business table -
    business_id = '67'
    business_name = 'planet pizza'

如何在前面显示这样的内容:

How do I display in the front something like this:

<ul>
<h2>the best 5 places</h2>
<li><span>1</span><?php echo $business_name ?></li>
<li><span>2</span><?php echo $business_name ?></li>
<li><span>3</span><?php echo $business_name ?></li>
<li><span>4</span><?php echo $business_name ?></li>
<li><span>5</span><?php echo $business_name ?></li>
</ul>

我已经在表中提供了 ID，所以我需要一些非常相似的东西，任何人都可以帮助我.

I already have the id's in the table so I need something very similar, can anyone pls help me.

感谢所有帮助问候

推荐答案

尝试使用此查询

SELECT * FROM business_table WHERE business_id IN ( SELECT business_id FROM ranking_table WHERE city='Boston' );

参见演示

你的代码，

$con=mysqli_connect("HOSTNAEM","USERNAME","PASSWORD","DB") die('Could not connect: ' . mysql_error());

$query = "SELECT * FROM business_table WHERE business_id IN ( SELECT business_id FROM ranking_table WHERE city='Boston' )";

while($row = mysqli_fetch_array($query))
{
  echo '<li><span>1</span>'+$row['$business_name']+'></li></br>';
}

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