查询用户在一对多表中的排名 [英] querying for user's ranking in one-to-many tables

问题描述

我正在尝试编写一个查询来查找用户游戏的得分排名.我需要它接收用户 ID，然后将该用户的相对排名返回到其他用户的分数.有一个用户和一个游戏桌.游戏表具有一对多关系的 userId 字段.

I am trying to write a query to find the score rank of a user's games. I need it to take in a user id and then return that user's relative ranking to other user's scores. There is a user and a game table. The game table has a userId field with a one-to-many relationship.

示例表:

用户:
id freebee
1 10
2 13

users:
id freebee
1 10
2 13

游戏:
用户 ID 分数
1 15
1 20
2 10
1 15

games:
userId score
1 15
1 20
2 10
1 15

将 $id 1 传递给这个函数应该返回值 1，因为用户 1 当前得分最高.同样，用户 2 将返回 2.

passing $id 1 into this function should return the value 1, as user 1 currently has the highest score. Likewise, user 2 would return 2.

目前这是我所拥有的:

SELECT outerU.id, (

SELECT COUNT( * )  
FROM users userI, games gameI  
WHERE userI.id = gameI.userId  
AND userO.id = gameO.userId  
AND (  
   userI.freebee + SUM(gameI.score)  
   ) >= ( userO.freebee + SUM(gameO.score) )  
) AS rank  
FROM users userO,  
games gameO  
WHERE id = $id

这给了我一个无效使用组功能"的错误.有什么想法吗?

Which is giving me an "invalid use of group function" error. Any ideas?

推荐答案

SELECT u.id,total_score,
 ( SELECT COUNT(*) FROM
    (SELECT u1.id, (IFNULL(u1.freebee,0)+ IFNULL(SUM(score),0)) as total_score
     FROM users u1
     LEFT JOIN games g ON (g.userId = u1.id)
     GROUP BY u1.id
    )x1
   WHERE x1.total_score > x.total_score
 )+1 as rank,

( SELECT COUNT(DISTINCT total_score) FROM
    (SELECT u1.id, (IFNULL(u1.freebee,0)+ IFNULL(SUM(score),0)) as total_score
     FROM users u1
     LEFT JOIN games g ON (g.userId_Id = u1.id)
     GROUP BY u1.id
    )x1
   WHERE x1.total_score > x.total_score
 )+1 as dns_rank

 FROM users u

 LEFT JOIN
  ( SELECT u1.id, (IFNULL(u1.freebee,0)+ IFNULL(SUM(score),0)) as total_score
    FROM users u1
    LEFT JOIN games g ON (g.userId = u1.id)
    GROUP BY u1.id
  )x ON (x.id = u.id)

rank -(正常等级 - 例如 - 1,2,2,4,5)，dns_rank - 密集等级(1,2,2,3,4).列 total_score - 仅用于调试...

rank - (normal rank - e.g. - 1,2,2,4,5), dns_rank - dense rank (1,2,2,3,4). Column total_score - just for debugging...

这篇关于查询用户在一对多表中的排名的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！