从数据库中读取前 10 行 [英] Read the top 10 rows from the database

问题描述

我一直在做这个小项目.我有一个看起来像这样的 MySQL 表

I have this small project I have been working on. I have a MySQL table that looks kind of like this

+---------+-------------+------+
| Content | Date Posted | Name |
+---------+-------------+------+
| Content | Date Posted | Name |
+---------+-------------+------+

我需要一个 PHP 脚本来根据发布日期从数据库中读取前 10 行.

And I need a PHP script to read the top 10 rows from the database, based on date posted.

推荐答案

您可以使用 PHPMyAdmin 创建表，或运行这样的脚本:

You can use PHPMyAdmin to create tables, or run a script like this:

CREATE TABLE Contents (
  Content MEMO NOT NULL,
  DatePosted DATE NOT NULL,
  Name VARCHAR2(200) NOT NULL);

然后像这样选择最新的 10 个:

and select the newest 10 like this:

SELECT
  t.Content,
  t.DatePosted,
  t.Name
FROM
  Contents t
ORDER BY
  DatePosted DESC
LIMIT 10

虽然答案看起来很小，但实际上是一个大问题.你不知道吗?如果您不想每次需要从数据库中获取一些内容时都卡住，也许您应该从阅读一些教程开始.

But while the answer seems small, it is actually a big question. Do you have no idea whatsoever? Maybe you should start by reading some tutorials if you don't want to get stuck every time you need a little something from your database.

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