Java 网络服务扫描器 [英] Java Network Service Scanner

问题描述

我正在尝试编写一个类来扫描本地网络以查找将要运行的服务.

I'm trying to write a class that will scan the local network for a service that will be running.

问题是，如果地址不活跃(没有回复)，它会在上面挂断 5 秒以上，这是不好的.

The problem is that if the address is not active (no reply) it hangs up on it for 5+ seconds which isn't good.

我想在几秒钟内完成此扫描.任何人都可以提供一些建议吗?

I want to have this scan done in a few seconds. Can anyone offer some advice?

我的代码部分在下面

        int port = 1338;
    PrintWriter out = null;
    BufferedReader in = null;

    for (int i = 1; i < 254; i++){

        try {
            System.out.println(iIPv4+i);
            Socket kkSocket = null;

            kkSocket = new Socket(iIPv4+i, port);

            kkSocket.setKeepAlive(false);
            kkSocket.setSoTimeout(5);
            kkSocket.setTcpNoDelay(false);  

            out = new PrintWriter(kkSocket.getOutputStream(), true);
            in = new BufferedReader(new InputStreamReader(kkSocket.getInputStream()));
            out.println("Scanning!");
            String fromServer;
            while ((fromServer = in.readLine()) != null) {
                System.out.println("Server: " + fromServer);
                if (fromServer.equals("Server here!"))
                    break;
            }

        } catch (UnknownHostException e) {

        } catch (IOException e) {

        }
    }

感谢您的回答！这是我为其他人寻找的代码！

Thank you for the answers! Here's my code for anyone else looking for this!

        for (int i = 1; i < 254; i++){

        try {
            System.out.println(iIPv4+i);
            Socket mySocket = new Socket();
            SocketAddress address = new InetSocketAddress(iIPv4+i, port);

            mySocket.connect(address, 5);   

            out = new PrintWriter(mySocket.getOutputStream(), true);
            in = new BufferedReader(new InputStreamReader(mySocket.getInputStream()));
            out.println("Scanning!");
            String fromServer;
            while ((fromServer = in.readLine()) != null) {
                System.out.println("Server: " + fromServer);
                if (fromServer.equals("Server here!"))
                    break;
            }

        } catch (UnknownHostException e) {

        } catch (IOException e) {

        }
    }

推荐答案

您可以尝试通过调用 Socket.connect( address, timeout ).

You could try connecting to the server explicitly by invoking Socket.connect( address, timeout ).

 Socket kkSocket = new Socket();
 kkSocket.bind( null )/ // bind socket to random local address, but you might not need to do this
 kkSocket.connect( new InetSocketAddress(iIPv4+i, port), 500 ); //timeout is in milliseconds

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