如何从两个数组列表中删除共同的价值观 [英] How to remove common values from two array list

问题描述

如何可以从两个ArrayList中删除共同的价值观。
让我们考虑我有两个数组列表如下图所示。

How can we remove common values from two ArrayList. lets consider i have two Arraylist as shown below

ArrayList1 = [1,2,3,4]
ArrayList1 = [2,3,4,6,7]

ArrayList1= [1,2,3,4] ArrayList1= [2,3,4,6,7]

我想有结果作为ArrayListFinal = [1,6,7]

I would like to have result as ArrayListFinal= [1,6,7]

任何人都可以请帮我。

由于提前

推荐答案

下面是你可以按照完成任务的算法：

Here is an algorithm that you could follow to accomplish the task:

• 构建两个数组的联合


• 构造两个数组的交集


• 从工会减去路口，让您的结果

Java集合支持<一个href=\"http://docs.oracle.com/javase/6/docs/api/java/util/Collection.html#addAll%28java.util.Collection%29\"><$c$c>addAll, <一href=\"http://docs.oracle.com/javase/6/docs/api/java/util/Collection.html#removeAll%28java.util.Collection%29\"><$c$c>removeAll,和<一个href=\"http://docs.oracle.com/javase/6/docs/api/java/util/Collection.html#retainAll%28java.util.Collection%29\"><$c$c>retainAll.使用的addAll 来构建工会，的retainAll 构建交叉口，和的removeAll 减法，这样：

Java collections support addAll, removeAll, and retainAll. Use addAll to construct unions, retainAll for constructing intersections, and removeAll for subtraction, like this:

// Make the two lists
List<Integer> list1 = Arrays.asList(1, 2, 3, 4);
List<Integer> list2 = Arrays.asList(2, 3, 4, 6, 7);
// Prepare a union
List<Integer> union = new ArrayList<Integer>(list1);
union.addAll(list2);
// Prepare an intersection
List<Integer> intersection = new ArrayList<Integer>(list1);
intersection.retainAll(list2);
// Subtract the intersection from the union
union.removeAll(intersection);
// Print the result
for (Integer n : union) {
    System.out.println(n);
}

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