带有内容的超时字符串 [英] timeout stringwithcontentsofurl

问题描述

我有这个对 stringwithcontentsofurl 的调用:

I have this call to stringwithcontentsofurl:

[NSString stringWithContentsOfURL:url usedEncoding:nil  error:nil];

我怎样才能给它一个简单的超时时间?我不想使用线程或操作队列(url的内容大约是100个字符)，我只是不想在连接慢的时候等待太久.

How can I give that a simple timeout? I don't want to use threads or operation queues (the content of the url is about 100 characters), I just don't want to wait too long when the connection is slow.

推荐答案

在这种情况下，您最好使用 NSURLConnection 类方法 +sendSynchronousRequest:returningResponse:error:;它会返回一个数据对象，你可以用它来初始化你的字符串(使用 -initWithData:encoding:).您可以通过使用 -initWithURL:cachePolicy:timeoutInterval: 方法创建 NSURLRequest 来指定超时，然后将该请求作为 +sendSynchronousRequest:returningResponse 的第一个参数传递:错误:.

In this case, you might be best off using the NSURLConnection class method +sendSynchronousRequest:returningResponse:error:; it'll return a data object you can initialize your string with (using -initWithData:encoding:). You can specify a timeout by creating an NSURLRequest using its -initWithURL:cachePolicy:timeoutInterval: method, then pass that request as the first parameter of +sendSynchronousRequest:returningResponse:error:.

这篇关于带有内容的超时字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！