xsl string-join() 多个变量 - 仅使用非空 [英] xsl string-join() multiple variables - only use non-empty

问题描述

我想创建几个 xsl:variable 可能是也可能不是 null 然后加入它们:

I'd like to create several xsl:variable that may or may not be null then join them:

<xsl:variable name="creatorType" select="replace(lib:merge(subfields/subfield[matches(@code,'[e]')],' '),'author|[.$]','')" />
<xsl:variable name="creatorAttribution" select="replace(lib:merge(subfields/subfield[matches(@code,'[j]')],' '),'[,-.]$','')" />
<xsl:variable name="creatorNameFullForm" select="replace(lib:merge(subfields/subfield[matches(@code,'[q]')],' '),'[,-()]$','')" />
<xsl:variable name="creatorAffiliation" select="replace(lib:merge(subfields/subfield[matches(@code,'[u]')],' '),'[,-.]$','')" />

string-join((xsl:sequence), 'delimiter') 看起来很合适，但也连接带有空值的变量.

string-join((xsl:sequence), 'delimiter') seems like a good fit but also joins variables with empty values.

<xsl:variable name="creatorDescriptors" select ="string-join(($creatorDates, $creatorType, $creatorAttribution, $creatorAffiliation),', ')"/>

你怎么会只有字符串连接非空 xsl:variables?

How would you have it only string-join non-null xsl:variables?

我目前得到这样的信息:

I'm currently getting something like this:

  Mozart, Wolfgang Amadeus (1756–1791, Composer, , )

推荐答案

试试这个表达式(用你自己的变量名替换变量名)，这样只会选择序列中的非空节点

Try this expression instead (replacing the variable names with your own variable names), so that only the non-empty nodes are selected in the sequence

<xsl:value-of select="string-join(($a, $b, $c, $d)[. != ''],', ')"/>

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