取两个可空值中的较大者 [英] Take the greater of two nullable values

问题描述

假设我有两个可为空的整数:

Suppose I have two nullable integers:

int? a = 10;
int? b = 20;

我想取最大的非空值，这样如果两个值都为空，则结果为空.

I want to take the biggest, non-null value, such that if both values are null, the result is null.

我可以写一些冗长的东西，例如:

I could write something long-winded such as:

int? max;
if (a == null)
{
    max = b;
}
else if (b == null)
{
    max = a;
}
else
{
    max = a > b ? a : b;
}

这对我来说感觉有点太笨重(并且可能容易出错).返回更大值的最简单方法是什么，这也说明了空值的可能性?

This feels a little too clunky (and possibly error-prone) for my liking. What's the simplest way to return the greater value, which also accounts for the possibility of null values?

推荐答案

这适用于任何可为 null 的:

This works for any nullable:

Nullable.Compare(a, b) > 0 ? a : b;

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