带有本地输入的 Python atof [英] Python atof with local input

问题描述

说，我有一个(德语)表达式，它读取 10.401,40(在 Mio EUR)，我想将其转换为真正的浮点数(在这种情况下约为 100 亿)蟒蛇.
这是我迄今为止所拥有的:

Say, I have a (German) expression which reads 10.401,40 (in Mio EUR), I'd like to convert this to a real float (in this case around 10 billions) in Python.
This is what I have thus far:

import re, locale
from locale import *
locale.setlocale(locale.LC_ALL, 'de_DE') 

string = "10.401,40 (in Mio EUR)"
m = re.search(r'([\d.,]+)', string)
if m is not None:
    number = atof(m.group(1)) * 10**6

但是，它会引发 ValueError(ValueError:float() 的无效文字:10.401.40).
为什么?.setlocale() 指令不是应该处理这个吗?有没有我(还！)不知道的 Pythonic 方式?

However, it raises a ValueError (ValueError: invalid literal for float(): 10.401.40).
Why? Isn't the .setlocale() directive supposed to be handling exactly this? Is there a pythonic way that I am (yet!) unaware of?

推荐答案

我遇到了相同的 ValueError.正如这个类似的问题所解释的，您需要在您的系统.按照上述操作，我输入 sudo dpkg-reconfigure locales 并选择 de-DE.UTF-8.我不得不修改语言环境设置行以匹配 locale.setlocale(locale.LC_ALL, 'de_DE.utf8') 并让您的代码段运行.祝你好运！

I got the same ValueError. As this similar question explains, you need to have the German locale installed in your system. Following the above, I typed in sudo dpkg-reconfigure locales and selected de-DE.UTF-8. I had to modify the locale setting line to match with locale.setlocale(locale.LC_ALL, 'de_DE.utf8') and got your snippet to run. Good luck!

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