将类添加到数字的第 n 位 [英] Adding Class to the nth Digit of Numbers

问题描述

有一个很好的方法在这个答案中 用于为页面中的每个数字添加一个 span.

There is a nice way in this answer for adding a span to every number in the page.

var regex = /(\d+)/,
    replacement = '<span>$1</span>';

function replaceText(el) {
    if (el.nodeType === 3) {
        if (regex.test(el.data)) {
            var temp_div = document.createElement('div');
            temp_div.innerHTML = el.data.replace(regex, replacement);
            var nodes = temp_div.childNodes;
            while (nodes[0]) {
                el.parentNode.insertBefore(nodes[0],el);
            }
            el.parentNode.removeChild(el);
        }
    } else if (el.nodeType === 1) {
        for (var i = 0; i < el.childNodes.length; i++) {
            replaceText(el.childNodes[i]);
        }
    }
}

replaceText(document.body);

是否可以将 span 添加到数字的每三位?我的意思是，不使用 Lettering.js.

Is it possible to add a span to the every third digit of the numbers? I mean, without using Lettering.js.

编辑

@thg435 已经回答了这个问题，但我发现他的第二个正则表达式 /\d(?=\d\d(\d{3})*\b 不适用于阿拉伯语我正在研究的数字.(阿拉伯数字从٠"到٩"开始，在正则表达式中可以被称为 [٠-٩].)可能，问题出在 \b 在第二个正则表达式的末尾.

@thg435 has already answered the question, but I dicovered that his second regex /\d(?=\d\d(\d{3})*\b does not work on Arabic numbers, which I'm working on. (Arabic numbers start from "٠" to "٩", and can be reffered as [٠-٩] in regex.) Probably, the problem is with the \b at the end of the second regex.

另外，作为我正在尝试/希望实现的一个例子，١٢٣٤ 应该变成 ١٢٣٤.

Also, as an example of what I'm trying/hoping to achieve, ١٢٣٤ should be turn into ١<span>٢</span>٣٤.

推荐答案

如果我理解正确

html = text.replace(/(\d\d)(\d)/g, function($0, $1, $2) {
      return $1 + "<span>" + $2 + "</span>" })

这将替换右边的每三个数字:

This replaces every third digit from the right:

> a = "foo 1234567890 bbb 123456"
"foo 1234567890 bbb 123456"
> a.replace(/\d(?=\d\d(\d{3})*\b)/g, "[$&]")
"foo 1[2]34[5]67[8]90 bbb [1]23[4]56"

对于阿拉伯数字，请考虑:

For arabic digits consider:

String.prototype.reverse = function() { return this.split("").reverse().join("") }
result = str.replace(/[\u0660-\u0669]+/g, function(s) {
    return s.
        reverse().
        replace(/(..)(.)/g, "$1aaa$2zzz").
        reverse().
        replace(/zzz(.)aaa/g, "<span>$1</span>")
})

它相当麻烦，但似乎有效:http://jsfiddle.net/VSTJs/2/

It's rather cumbersome, but appears to work: http://jsfiddle.net/VSTJs/2/

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