需要对解释如何code处理ArrayList的价值观 [英] Need explanations on how this code processes Arraylist values
问题描述
public static void mystery1(ArrayList<Integer> list) {
for (int i = list.size() - 1; i > 0; i--) {
if (list.get(i) < list.get(i - 1)) {
int element = list.get(i);
list.remove(i);
list.add(0, element);
}
}
System.out.println(list);
}
我试图用给定的套 ArrayList的值
,解决了此方法的输出。看在它之后,我是pretty肯定这code将重新定位在列表的前面的一对较小的值。我使用的值的ArrayList [2,6,1,8]
输入,结果是 [1,2,6,8]
,这是如我所料。但对于 [30,20,10,60,50,40]
它产生 [10,30,40,20,60,50]
时,我期望 [40,50,10,20,30,60]
。因此,任何人都可以请向我解释这code实际上是如何处理的ArrayList
?谢谢!
I'm trying to solve the for the output of this method with given sets of ArrayList values
. After looking over it, I was pretty sure this code would relocate the smaller value of a pair in the front of the list. I used an ArrayList of values [2, 6, 1, 8]
for input and the result was [1, 2, 6, 8]
, which was as I expected. But for [30, 20, 10, 60, 50, 40]
it produced [10, 30, 40, 20, 60, 50]
when I expected [40,50,10,20,30,60]
. Therefore can anyone please explain to me how this code actually processes the Arraylist
? Thanks!
推荐答案
下面是一步情况,步:
- 您的列表的初始状态:[30,20,10,60,50,40]
- 是40℃,50?是。所以除去40,并把它作为列表的第一个元素:[40,30,20,10,60,50]
- 是60℃,10?号不碰任何东西:[40,30,20,10,60,50]
- 是10小于20?是。所以除去10,并把它作为列表的第一个元素:[10,40,30,20,60,50]
- 是30℃,40?是。所以除去30,并把它作为列表的第一个元素:[30,10,40,20,60,50]
- 10小于30?是。所以除去10,并把它作为列表的第一个元素:[10,30,40,20,60,50]
其结果是,则:[10,30,40,20,60,50]
The result is then: [10, 30, 40, 20, 60, 50]
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