使用Java的ArrayList存储的ResultSet从数据库中获得的新手尝试 [英] newbie attempt to use Java ArrayList to store ResultSet obtained from database
问题描述
我有一个数据库服务器使用JDBC的Java应用程序服务器进行通信。我想将数据从数据库结果集到Java变量存储。
下面是我的Java类,HRPeople:
公共类HRPeople {
公众诠释要素;
公众的String []名字;
公众的String []姓氏;
公众的String []电子邮件;
公众诠释[]工资;
}
我目前使用这个类来存储来自ResultSet中的数据,如下:
查询=SELECT名字,姓氏,电子邮件,工资从HR.EMPLOYEES哪里ROWNUM 6;;
RSET = stmt.executeQuery(查询);
而(rset.next()){
returnHRdata.FirstName [Ⅱ] = rset.getString(如first_name);
returnHRdata.LastName [Ⅱ] = rset.getString(姓氏);
returnHRdata.Email [II] = rset.getString(电子邮件);
returnHRdata.Salary [II] = rset.getInt(工资);
二= II + 1;
}
与上述方案的问题是,在原始的阵列需要我知道在结果集中的行数,这样我可以正确初始化这些阵列。因此,我想要做的就是使用ArrayList来代替。我将如何修改上面的场景做到这一点?
下面是我最初的尝试(这是接近)?以上,即使在这种情况下使用的显示HRPeople.java文件?
查询=SELECT名字,姓氏,电子邮件,工资从HR.EMPLOYEES哪里ROWNUM 6;;
RSET = stmt.executeQuery(查询);
清单< HRPeople> returnHRdata =新的ArrayList< HRPeople>();
而(rset.next()){
returnHRdata.FirstName = rset.getString(FIRST_NAME);
returnHRdata.LastName = rset.getString(姓氏);
returnHRdata.Email = rset.getString(电子邮件);
returnHRdata.Salary = rset.getInt(工资);
returnHRdata.add;
}
更新1:
如果我添加到code以下,
收益returnHRdata;
我收到以下错误(任何想法,为什么?)
myClass.java:213:不兼容的类型
发现:java.util.List的< HRPerson>
要求:java.util.ArrayList中< HRPerson>
返回returnHRdata;
^
1个错误
您可能要首先定义一个像这样的HRPerson:
公共类HRPerson {
公共字符串的firstName;
公共字符串的lastName;
公共字符串的电子邮件;
公众诠释的工资;
}
然后你的主code看起来像:
查询=SELECT名字,姓氏,电子邮件,工资从HR.EMPLOYEES哪里ROWNUM 6;;
RSET = stmt.executeQuery(查询);
清单< HRPerson> returnHRdata =新的ArrayList< HRPerson>();
而(rset.next()){
HRPerson人=新HRPerson();
person.firstName = rset.getString(FIRST_NAME);
person.lastName = rset.getString(姓氏);
person.email = rset.getString(电子邮件);
person.salary = rset.getInt(工资);
returnHRdata.add(人);
}
I have a database server communicating with a Java application server using JDBC. I want to store data from the database ResultSet into Java variables.
Here's my Java class, HRPeople:
public class HRPeople {
public int elements;
public String[] FirstName;
public String[] LastName;
public String[] Email;
public int[] Salary;
}
I currently use this class to store data from ResultSet, as follows:
query = "SELECT first_name, last_name, email, salary FROM HR.Employees where rownum < 6";
rset = stmt.executeQuery(query);
while (rset.next()) {
returnHRdata.FirstName[ii] = rset.getString("first_name");
returnHRdata.LastName[ii] = rset.getString("last_name");
returnHRdata.Email[ii] = rset.getString("email");
returnHRdata.Salary[ii] = rset.getInt("salary");
ii = ii + 1;
}
The problem with the above scenario is that the primitive arrays require me to know the number of rows in the ResultSet so that I can properly initialize those arrays. So what I want to do is use an ArrayList instead. How would I modify the above scenario to do this?
Here's my initial attempt (is this close)? Is HRPeople.java file shown above even used in this scenario?
query = "SELECT first_name, last_name, email, salary FROM HR.Employees where rownum < 6";
rset = stmt.executeQuery(query);
List<HRPeople> returnHRdata = new ArrayList<HRPeople>();
while (rset.next()) {
returnHRdata.FirstName = rset.getString("first_name");
returnHRdata.LastName = rset.getString("last_name");
returnHRdata.Email = rset.getString("email");
returnHRdata.Salary = rset.getInt("salary");
returnHRdata.add;
}
UPDATE 1:
If I add to the code the following,
return returnHRdata;
I get the following error (any idea why?):
myClass.java:213: incompatible types
found : java.util.List<HRPerson>
required: java.util.ArrayList<HRPerson>
return returnHRdata;
^
1 error
You probably want to first define an HRPerson like this:
public class HRPerson {
public String firstName;
public String lastName;
public String email;
public int salary;
}
Then your main code would look like:
query = "SELECT first_name, last_name, email, salary FROM HR.Employees where rownum < 6";
rset = stmt.executeQuery(query);
List<HRPerson> returnHRdata = new ArrayList<HRPerson>();
while (rset.next()) {
HRPerson person = new HRPerson();
person.firstName = rset.getString("first_name");
person.lastName = rset.getString("last_name");
person.email = rset.getString("email");
person.salary = rset.getInt("salary");
returnHRdata.add(person);
}
这篇关于使用Java的ArrayList存储的ResultSet从数据库中获得的新手尝试的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!