jQuery从对象集合中删除对象 [英] jQuery remove object from object collection

问题描述

我有以下示例代码，用于创建对象集合.

I have the following example code, creating a object collection.

如何移除其中一个对象?(例如， $TestList 看起来好像删除我"项从未存在过.我试过 .remove、.splice、.delete 等，但我被告知这不是一个函数.

How can I remove one of the objects? (e.g. $TestList would look as though the "delete me" item was never there. I've tried .remove, .splice, .delete etc but I'm told it's not a function.

执行 typeof($TestList) 会带回对象，而 typeof($TestList[0]) 似乎也有效.

Doing typeof($TestList) brings back object, and typeof($TestList[0]) also seems valid.

当然我不必在没有一件物品的情况下重新创建集合吗?

Surely I don't have to recreate the collection without one item?

(function($) { 

jQuery.QuickTest = {
    $TestList: {},
    build: function()
    {
        $TestList={};
        $TestList[0] = 
        {
            title: "part 1"
        };

        $TestList[1] = 
        {
            title: "delete me please"
        };

        $TestList[2] = 
        {
            title: "part 2"
        };

    }
}

jQuery.fn.QuickTest = jQuery.QuickTest.build;   

})(jQuery);

$(document).ready(function() {

$().QuickTest(
{
})
});

我们使用的是 jQuery 1.3.

We're using jQuery 1.3.

谢谢！

推荐答案

回顾

首先，您的代码应该做什么非常不明显，但这里有一些问题:

First of all, it's very non-obvious what your code is supposed to do, but here are some issues:

jQuery.QuickTest = {
    $TestList: {},
    build: function()
    {
        $TestList={};

你定义了 jQuery.QuickTest.$TestList，但是在 build() 里面你声明了一个 global 对象 $TestList.

You define jQuery.QuickTest.$TestList, but inside build() you declare a global object $TestList.

在 jQuery.fn 下声明的函数应该作用于一组匹配的元素(由 this 引用)并返回它；你的函数两者都没有.

Functions declared under jQuery.fn are supposed to act on a matched set of elements (referenced by this) and return it as well; your function does neither.

答案

回答您的一些问题:

1. .remove() 是一个 jQuery 函数，用于从 DOM 中删除节点，需要在 jQuery 对象上调用.

1. .remove() is a jQuery function that removes nodes from the DOM and needs to be called on a jQuery object.

.splice() 仅适用于 Array 并且即使您像访问 $TestList 一样访问它，它仍然只是一个 Object.

.splice() only applies to Array and even though you're accessing $TestList as if it were one, it's still just an Object.

.delete() 不是我知道的任何函数;-)

.delete() is not any function I know ;-)

可能的解决方案

要从 $TestList 中删除条目，您可以以这种方式使用 delete:

To delete an entry from $TestList you could use the delete in this fashion:

delete $TestList[1];

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