合并两个 Javascript 对象，每个键有多个匹配项 [英] Merge Two Javascript Objects with Multiple Matches Per Key
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问题描述
我有两个要合并的对象.我几乎成功地解决了这个问题的答案(Merge两个键不同但值相同的无序对象?).
I have two objects which I am trying to merge. I am almost successfully worked with answer from this question (Merge two unordered objects with different keys but same value?).
问题是在我的transpatterns"对象中，我有两种模式与Intercom"键匹配.但是，在我的输出中，它只需要第二个.我需要它在同一个键下列出两者.
The issue is that in my "transpatterns" object, I have two patterns that match "Intercom" key. However, in my output, it only takes the second one. I need it to list both under the same key.
这是我的代码:
var hash = {};
var partitions = [{
'$': {
uuid: '{0F314A21-B066-B597-BCFA-6EC88CF8813B}'
},
name: ['AllPhones']
},
{
'$': {
uuid: '{4DCF3A89-ADA1-2770-4154-F6E0204D9A71}'
},
name: ['Unity_Connection']
},
{
'$': {
uuid: '{B653BC00-2D90-790C-AE0D-16C3DD2F8EDD}'
},
name: ['LAB-Tansform-Calling']
},
{
'$': {
uuid: '{148C8971-87E4-49D3-1536-69B6C95293B3}'
},
name: ['Blocked']
},
{
'$': {
uuid: '{25534E0F-F69A-FDDB-2FAD-34312BB6CEFC}'
},
name: ['LAB-PSTN-Sim-911']
},
{
'$': {
uuid: '{EC1E144B-2C8C-22CC-F1F5-423CF0343367}'
},
name: ['LAB-PSTN-Sim-Local']
},
{
'$': {
uuid: '{9C7F3223-AE2D-7605-C642-0CEAB81CD555}'
},
name: ['LAB-PSTN-Sim-LD']
},
{
'$': {
uuid: '{15AFADC3-859B-2806-B9D1-5678CE035E3D}'
},
name: ['LAB-PSTN-Sim-Intl']
},
{
'$': {
uuid: '{5DD43CF0-5FB0-A6A0-A71D-D284265F37C7}'
},
name: ['Agents']
},
{
'$': {
uuid: '{7FDE7E11-F821-2491-BB08-E6A41DAB205D}'
},
name: ['UCCX']
},
{
'$': {
uuid: '{17500618-9567-92B9-8C15-95D794094A3F}'
},
name: ['Intercom']
},
{
'$': {
uuid: '{77049844-AB06-F899-26D0-C0940E20D4D5}'
},
name: ['Netech_Managers']
},
{
'$': {
uuid: '{A9DD47E0-1C4A-AAB9-E859-E6EEDB26E6B0}'
},
name: ['Assistant_Route_Point']
}
];
var transpatterns = [{
'$': {
uuid: '{3FF82ECB-7364-41DB-176B-65D28885339F}'
},
pattern: ['9.19005554444'],
description: ['Sample Outbound Call Block'],
routePartitionName: ['Blocked']
},
{
'$': {
uuid: '{18C2C829-AFAE-DB28-A003-5F1731907D85}'
},
pattern: ['555555XXXX'],
description: ['Inbound DID Range'],
routePartitionName: ['AllPhones']
},
{
'$': {
uuid: '{465EFEF8-C405-8D30-2C97-4BF9907C92C6}'
},
pattern: ['3100'],
description: ['Intercom Xlate'],
routePartitionName: ['Intercom']
},
{
'$': {
uuid: '{C17E117C-41C7-D459-8CD1-B1D3C4EDC40D}'
},
pattern: ['3101'],
description: ['Intercom Xlate'],
routePartitionName: ['Intercom']
}
];
// TESTING NEW
// COMBINE OBJECTS - CREATE HASH
function classify(e) {
if (hash[e.name] || hash[e.routePartitionName]) {
Object.keys(e).forEach(function (c) {
hash[e.name || e.routePartitionName][c] = e[c];
});
} else {
hash[e.routePartitionName || e.name] = e;
}
}
// COMBINE OBJECTS - ADD VARS to HASH
partitions.forEach(classify);
transpatterns.forEach(classify);
// COMBINE OBJECTS - ITERATE HASH + REMOVE ANY FIELDS
var combo = Object.keys(hash).map(function (e) {
delete hash[e]['routePartitionName'];
return hash[e];
});
console.log(combo);推荐答案
我能够解决我的问题.我确定在合并两个对象之前，我需要折叠具有与同一键关联的多个项目的对象.我能够使用这个问题的答案来帮助我做到这一点.如何组合JSON具有相同键的对象并添加其他对应的值?
I was able to solve my problem. I determined that I needed to collapse the object with multiple items associated with the same key before I merged the two objects. I was able to use the answer from this question to help me do this. How to combine JSON object with same key and add their other corresponding values?
这是我想出的代码，看起来运行良好.
Here is the code I came up with that seems to work nicely.
// DEFINE VARIABLES
var partitions = [{
'$': {
uuid: '{0F314A21-B066-B597-BCFA-6EC88CF8813B}'
},
name: ['AllPhones']
},
{
'$': {
uuid: '{4DCF3A89-ADA1-2770-4154-F6E0204D9A71}'
},
name: ['Unity_Connection']
},
{
'$': {
uuid: '{B653BC00-2D90-790C-AE0D-16C3DD2F8EDD}'
},
name: ['LAB-Tansform-Calling']
},
{
'$': {
uuid: '{148C8971-87E4-49D3-1536-69B6C95293B3}'
},
name: ['Blocked']
},
{
'$': {
uuid: '{25534E0F-F69A-FDDB-2FAD-34312BB6CEFC}'
},
name: ['LAB-PSTN-Sim-911']
},
{
'$': {
uuid: '{EC1E144B-2C8C-22CC-F1F5-423CF0343367}'
},
name: ['LAB-PSTN-Sim-Local']
},
{
'$': {
uuid: '{9C7F3223-AE2D-7605-C642-0CEAB81CD555}'
},
name: ['LAB-PSTN-Sim-LD']
},
{
'$': {
uuid: '{15AFADC3-859B-2806-B9D1-5678CE035E3D}'
},
name: ['LAB-PSTN-Sim-Intl']
},
{
'$': {
uuid: '{5DD43CF0-5FB0-A6A0-A71D-D284265F37C7}'
},
name: ['Agents']
},
{
'$': {
uuid: '{7FDE7E11-F821-2491-BB08-E6A41DAB205D}'
},
name: ['UCCX']
},
{
'$': {
uuid: '{17500618-9567-92B9-8C15-95D794094A3F}'
},
name: ['Intercom']
},
{
'$': {
uuid: '{77049844-AB06-F899-26D0-C0940E20D4D5}'
},
name: ['Netech_Managers']
},
{
'$': {
uuid: '{A9DD47E0-1C4A-AAB9-E859-E6EEDB26E6B0}'
},
name: ['Assistant_Route_Point']
}
];
var transpatterns = [{
'$': {
uuid: '{3FF82ECB-7364-41DB-176B-65D28885339F}'
},
pattern: ['9.19005554444'],
description: ['Sample Outbound Call Block'],
routePartitionName: ['Blocked']
},
{
'$': {
uuid: '{18C2C829-AFAE-DB28-A003-5F1731907D85}'
},
pattern: ['555555XXXX'],
description: ['Inbound DID Range'],
routePartitionName: ['AllPhones']
},
{
'$': {
uuid: '{465EFEF8-C405-8D30-2C97-4BF9907C92C6}'
},
pattern: ['3100'],
description: ['Intercom Xlate'],
routePartitionName: ['Intercom']
},
{
'$': {
uuid: '{C17E117C-41C7-D459-8CD1-B1D3C4EDC40D}'
},
pattern: ['3101'],
description: ['Intercom Xlate'],
routePartitionName: ['Intercom']
}
];
var hash = {};
// FUNCTION - COMBINE ITEMS WITHIN OBJECT - WITH SAME KEY:routePartitionName
function combine(arr) {
var combined = arr.reduce(function (result, item) {
var current = result[item.routePartitionName];
result[item.routePartitionName] = !current ? item : {
pattern: current.pattern + ',' + item.pattern,
description: item.description,
routePartitionName: item.routePartitionName
};
return result;
}, {});
return Object.keys(combined).map(function (key) {
return combined[key];
});
}
// FUNCTION - COMBINE ITEMS WITHIN OBJECT - RUN
var result = combine(transpatterns);
// FUNCTION - COMBINE OBJECTS - CREATE HASH
function classify(e) {
if (hash[e.name] || hash[e.routePartitionName]) {
Object.keys(e).forEach(function (c) {
hash[e.name || e.routePartitionName][c] = e[c];
});
} else {
hash[e.routePartitionName || e.name] = e;
}
}
// FUNCTION - COMBINE OBJECTS - ADD VARS to HASH
partitions.forEach(classify);
result.forEach(classify);
// FUNCTION - COMBINE OBJECTS - ITERATE HASH + REMOVE ANY FIELDS
var combo = Object.keys(hash).map(function (e) {
delete hash[e]['routePartitionName'];
delete hash[e]['$'];
return hash[e];
});
console.log(combo);这篇关于合并两个 Javascript 对象，每个键有多个匹配项的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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