如何用命名空间解析 XML 文件? [英] How parsing out XML file with namespaces?

问题描述

我知道之前有人发布过类似的问题，但我无法解析出带有命名空间的 XML 文件.

I know similar questions were posted before, but I can't parse out this XML file with namespaces.

这是它的链接，因为它太大了，不能在这里发布:https://tsdrapi.uspto.gov/ts/cd/casestatus/sn86553893/info.xml

Here is the link to it because it's too big to post here: https://tsdrapi.uspto.gov/ts/cd/casestatus/sn86553893/info.xml

我尝试使用 simplexml_load_file 但这不会创建 xml 对象.然后我发现了类似的问题并尝试了类似的方法，前提是我已经下载了名为 86553893.xml 的文件

I tried using simplexml_load_file but that does not create xml object. Then I found similar problems and try something like this, provided I already downloaded file named it 86553893.xml

这是我的php代码:

$xml= new SimpleXMLElement("86553893.xml");
                            foreach($xml->xpath('//com:ApplicationNumber') as $event) {
                                var_export($event->xpath('com:ApplicationNumberText'));
                        }

推荐答案

您必须在要使用的每个元素上注册命名空间:

You will have to register the namespaces on each element you want to use them:

$xml= new SimpleXMLElement("86553893.xml");
$xml->registerXpathNamespace('com', 'http://www.wipo.int/standards/XMLSchema/Common/1');
foreach ($xml->xpath('//com:ApplicationNumber') as $event) {
  $event->registerXpathNamespace(
    'com', 'http://www.wipo.int/standards/XMLSchema/Common/1'
  );                         
  var_export($event->xpath('com:ApplicationNumberText'));
}

这在 DOM 中有所不同，您使用 DOMXPath 实例，因此它只是一个对象，您只需注册一次命名空间.

This is different in DOM, you use an DOMXPath instance, so it is only a single object and you will have to register the namespaces only once.

$dom = new DOMDocument();
$dom->load("86553893.xml");
$xpath = new DOMXpath($dom);
$xpath->registerNamespace('com', 'http://www.wipo.int/standards/XMLSchema/Common/1');

foreach ($xpath->evaluate('//com:ApplicationNumber') as $event) {
  var_export($xpath->evaluate('string(com:ApplicationNumberText)', $event));
}

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