手表套件:是否可以以编程方式振动手表? [英] Watch Kit: is it possible to vibrate watch programmatically?

问题描述

手表扩展程序运行时是否可以振动手表?我们可以在 iOS 上这样操作(强制 iPhone 振动):

Is it possible to vibrate watch while Watch Extension is running? We can do it on iOS in this way (force iPhone to vibrate):

AudioServicesPlaySystemSound(kSystemSoundID_Vibrate);

我希望 WatchKit 上也有类似的东西.

I hope there is something similar on WatchKit.

更新:我已将问题添加到 Apple 雷达并收到了答案:

Update: I have added issue to Apple radar and recieved the answer:

工程部已确定您的错误报告 (20019274) 与另一个问题 (19025053) 重复，因此将关闭.

Engineering has determined that your bug report (20019274) is a duplicate of another issue (19025053) and will be closed.

19025053 仍然打开.

19025053 is still open.

更新 2: AudioServicesPlayAlertSound() 不适用于具有任何声音 ID 的手表模拟器.好像不支持函数.

Update 2: AudioServicesPlayAlertSound() not working on watch simulator with any sound ID. Seems like function is not supported.

推荐答案

如果您的目标是 watchOS 2.0

要做到这一点，您需要做的就是在具有任何 WKHapticType 的 WKInterfaceDevice 实例上调用 playHaptic.在下面的示例中，它将播放通知触觉.

To do this all you need to do is call playHaptic on a WKInterfaceDevice instance with any WKHapticType. In the example below it will play the notification haptic.

Swift 3

WKInterfaceDevice.current().play(.notification)

目标 C

[[WKInterfaceDevice currentDevice] playHaptic:WKHapticTypeNotification];

您可以进一步阅读Apple WKInterfaceDevice 文档

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