如何在 iPhone SDK 中舍入浮点值并将其转换为 NSInteger 值? [英] How to round an float value and convert it into NSInteger value in the iPhone SDK?

问题描述

我需要舍入一个浮点值并将其转换为 NSInteger 值.

I need to round a float value and convert it into an NSInteger value.

例如:

float f = 90.909088;

我希望结果是 91.如何摆脱这个?

I want the result to be 91. How to get rid of this?

推荐答案

以下 C 数学函数之一可能适合您:

One of the following C math functions might work for you:

• 双天花板(双)
• 双层(双人)
• double nearint(double)
• double rint(double)
• 双轮(双)
• long int lint(double)
• long int lround(double)
• long long int llrint(double)
• long long int llround(double)
• 双截断(双)

要获取更多文档，请打开终端会话并输入(例如)

To get more documentation, open a terminal session and type (for example)

man lround

我选择 lround 作为示例，因为我认为那是您想要的.

I pick lround as an example because I think that is the one you want.

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