如何在Objective-C中使用带有inout参数的Swift方法? [英] How can method in Swift with inout parameter be used in Objective-C?

问题描述

我想要

func foo(inout stop: Bool) -> Void {
    // ...
}

在我的 Objective-C 部分使用.但它永远不会在 Module-Swift.h 头文件中生成.如果我用@objc 标记它，

use in my Objective-C part. But it is never generated in Module-Swift.h header. If I mark it with @objc, the

方法不能被标记@objc 因为参数的类型不能用 Objective-C 表示

Method cannot be marked @objc because the type of the parameter cannot be represented in Objective-C

发生错误.

推荐答案

在与 Objective-C 桥接时，您不能使用 inout 参数，但是如果您使用 inout 参数，则可以执行类似的操作code>UnsafeMutablePointer<T>(在您的情况下，T 将是 Bool).它看起来像这样:

You can't use an inout parameter when bridging with Objective-C, but you can do something similar if you use an UnsafeMutablePointer<T> (T would be Bool in your case). It would look something like this:

@objc func foo(stop: UnsafeMutablePointer<Bool>) -> Void {
    if stop != nil {
        // Use the .pointee property to get or set the actual value stop points to
        stop.pointee = true
    }
}

<小时>

示例

TestClass.swift:

---

Example

TestClass.swift:

public class TestClass: NSObject {
    @objc func foo(stop: UnsafeMutablePointer<Bool>) -> Void {
        stop.pointee = true
    }
}

目标-C:

TestClass *test = [[TestClass alloc] init];
BOOL stop = false;
[test foo:&stop];
// stop is YES here

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